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standard hydrogen electrode exqam question

heres the exam question: when Pb2+/Pb half cell is connected to standard hydrogen electrode the reading on the voltmeter is -0.13V
what is the standard electroe potential for Pb2+/Pb half cell?
is reduction or oxidation taking place?

I learnt that when dealing with standard hydrogen electrodes, oxidation always occurs with the h2 electrode and its 0V, it should always be in the left hand side in diagrams and cell representations etc. so why is it contradicted here? the actual answer is -0.13V and oxidation is occurring, but I put the opposite answers +0.13V reduction
The H2 electrode is 0.00V and the Pb2+/Pb half cell is -0.13V

The standard electrode potential for a half cell is the reading on the voltmeter when connected to a H electrode (with the H electrode connected to the negative terminal on the voltmeter) and the question says that it is -0.13V so that is the answer.
The most negative half cell undergoes oxidation so the Pb2+/Pb half cell is undergoing oxidation.
Reply 2
thank u so much
Original post by Madasahatter
The H2 electrode is 0.00V and the Pb2+/Pb half cell is -0.13V

The standard electrode potential for a half cell is the reading on the voltmeter when connected to a H electrode (with the H electrode connected to the negative terminal on the voltmeter) and the question says that it is -0.13V so that is the answer.
The most negative half cell undergoes oxidation so the Pb2+/Pb half cell is undergoing oxidation.
Reply 3
****... the universe is imploding while fusion occurs. It will try to continue until expansion rips it apart! Offset local fusion along with the red shift of universal expansion and voila! It is doing what nature does... seeking stability.

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