# Maths question help! Problem solving - NO CALC Watch

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I am unsure of to achieve the answer for this? Any help...

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What is the area of an equilateral triangle with a base of ‘x’.

Options:

- (root 2)(6-(root 2))

- 6(4-(root 2))

- 6(root 2)

- 2(6-(root 2))

- (root 2)(4-(root 2))

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

Options:

- (root 2)(6-(root 2))

- 6(4-(root 2))

- 6(root 2)

- 2(6-(root 2))

- (root 2)(4-(root 2))

Last edited by Soohiiii; 3 weeks ago

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#2

(Original post by

I am unsure of to achieve the answer for this? Any help...

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What is the area of an equilateral triangle with a base of ‘x’.

**Soohiiii**)I am unsure of to achieve the answer for this? Any help...

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What is the area of an equilateral triangle with a base of ‘x’.

So drop a perpendicular from the top to the base and the vertical height can be simply determined in terms of x, using the fact that the triangle is equilateral). Base is x.

Then its just

base*verticalHeight/2

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#3

**Soohiiii**)

I am unsure of to achieve the answer for this? Any help...

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What is the area of an equilateral triangle with a base of ‘x’.

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I understand but I can’t seem to find one of the answer options

(Original post by

All sides are x (equilateral).

So drop a perpendicular from the top to the base and the vertical height can be simply determined in terms of x, using the fact that the triangle is equilateral). Base is x.

Then its just

base*verticalHeight/2

**mqb2766**)All sides are x (equilateral).

So drop a perpendicular from the top to the base and the vertical height can be simply determined in terms of x, using the fact that the triangle is equilateral). Base is x.

Then its just

base*verticalHeight/2

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#5

(Original post by

I understand but I can’t seem to find one of the answer options

**Soohiiii**)I understand but I can’t seem to find one of the answer options

Have you a value for x as you've edited post 1.

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(Original post by

The quickest way is to use Area = 1/2 ab sin(C). Since it's an equilateral triangle you should know what the angle (C) is.

**Sir Cumference**)The quickest way is to use Area = 1/2 ab sin(C). Since it's an equilateral triangle you should know what the angle (C) is.

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#7

(Original post by

You can’t do this without a calculator though

**Soohiiii**)You can’t do this without a calculator though

What is x, they must give you a value?

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#8

(Original post by

You can’t do this without a calculator though

**Soohiiii**)You can’t do this without a calculator though

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#9

(Original post by

I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

Options:

- (root 2)(6-(root 2))

- 6(4-(root 2))

- 6(root 2)

- 2(6-(root 2))

- (root 2)(4-(root 2))

**Soohiiii**)I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

Options:

- (root 2)(6-(root 2))

- 6(4-(root 2))

- 6(root 2)

- 2(6-(root 2))

- (root 2)(4-(root 2))

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(Original post by

What do you think it is and what are the options?

Have you a value for x as you've edited post 1.

**mqb2766**)What do you think it is and what are the options?

Have you a value for x as you've edited post 1.

(Original post by

Please post a picture of the question. It doesn’t make sense what you’ve posted here.

**Sir Cumference**)Please post a picture of the question. It doesn’t make sense what you’ve posted here.

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**Sir Cumference**)

Please post a picture of the question. It doesn’t make sense what you’ve posted here.

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#12

(Original post by

There is now a picture

**Soohiiii**)There is now a picture

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#13

**Soohiiii**)

I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

Options:

- (root 2)(6-(root 2))

- 6(4-(root 2))

- 6(root 2)

- 2(6-(root 2))

- (root 2)(4-(root 2))

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(Original post by

So I'm guessing that the options you've posted here are incorrect and meant for another question?

**Sir Cumference**)So I'm guessing that the options you've posted here are incorrect and meant for another question?

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(Original post by

So how long is each side and what are the angles?

**mqb2766**)So how long is each side and what are the angles?

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#16

(Original post by

It’s whatever is on the picture

**Soohiiii**)It’s whatever is on the picture

You should try and put a bit of effort into answering these questions. They're meant to help you learn.

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#17

(Original post by

They are the same as in the picture

**Soohiiii**)They are the same as in the picture

Options:

- (root 2)(6-(root 2))

- 6(4-(root 2))

- 6(root 2)

- 2(6-(root 2))

- (root 2)(4-(root 2))

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#18

(Original post by

It’s whatever is on the picture

**Soohiiii**)It’s whatever is on the picture

Can

**you**please tell use what you think the angles in the triangle are since it's equilateral?

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#19

1/2 × ab × sin60=1/2 × X^2 × (root3/2)= root3/4 × X^2 which is B

Last edited by Txeded; 3 weeks ago

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(Original post by

Ok, I'll drop out here.

You should try and put a bit of effort into answering these questions. They're meant to help you learn.

**mqb2766**)Ok, I'll drop out here.

You should try and put a bit of effort into answering these questions. They're meant to help you learn.

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