Maths question help! Problem solving - NO CALC Watch

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Soohiiii
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#1
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#1
I am unsure of to achieve the answer for this? Any help...

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What is the area of an equilateral triangle with a base of ‘x’.

Options:
- (root 2)(6-(root 2))
- 6(4-(root 2))
- 6(root 2)
- 2(6-(root 2))
- (root 2)(4-(root 2))
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mqb2766
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(Original post by Soohiiii)
I am unsure of to achieve the answer for this? Any help...

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What is the area of an equilateral triangle with a base of ‘x’.
All sides are x (equilateral).
So drop a perpendicular from the top to the base and the vertical height can be simply determined in terms of x, using the fact that the triangle is equilateral). Base is x.
Then its just
base*verticalHeight/2
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Sir Cumference
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(Original post by Soohiiii)
I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.
The quickest way is to use Area = 1/2 ab sin(C). Since it's an equilateral triangle you should know what the angle (C) is.
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Soohiiii
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I understand but I can’t seem to find one of the answer options
(Original post by mqb2766)
All sides are x (equilateral).
So drop a perpendicular from the top to the base and the vertical height can be simply determined in terms of x, using the fact that the triangle is equilateral). Base is x.
Then its just
base*verticalHeight/2
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mqb2766
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(Original post by Soohiiii)
I understand but I can’t seem to find one of the answer options
What do you think it is and what are the options?

Have you a value for x as you've edited post 1.
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Soohiiii
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(Original post by Sir Cumference)
The quickest way is to use Area = 1/2 ab sin(C). Since it's an equilateral triangle you should know what the angle (C) is.
You can’t do this without a calculator though
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mqb2766
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(Original post by Soohiiii)
You can’t do this without a calculator though
You don't need one.
What is x, they must give you a value?
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Sir Cumference
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(Original post by Soohiiii)
You can’t do this without a calculator though
The sine value that you require is one of the ones that you would have learnt at GCSE - you’re expected to know it without using a calculator.
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Sir Cumference
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(Original post by Soohiiii)
I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

Options:
- (root 2)(6-(root 2))
- 6(4-(root 2))
- 6(root 2)
- 2(6-(root 2))
- (root 2)(4-(root 2))
Please post a picture of the question. It doesn’t make sense what you’ve posted here.
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Soohiiii
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(Original post by mqb2766)
What do you think it is and what are the options?

Have you a value for x as you've edited post 1.
(Original post by Sir Cumference)
Please post a picture of the question. It doesn’t make sense what you’ve posted here.
I have attached a picture now
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Soohiiii
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(Original post by Sir Cumference)
Please post a picture of the question. It doesn’t make sense what you’ve posted here.
There is now a picture
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mqb2766
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(Original post by Soohiiii)
There is now a picture
So how long is each side and what are the angles?
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Sir Cumference
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(Original post by Soohiiii)
I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

Options:
- (root 2)(6-(root 2))
- 6(4-(root 2))
- 6(root 2)
- 2(6-(root 2))
- (root 2)(4-(root 2))
So I'm guessing that the options you've posted here are incorrect and meant for another question?
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Soohiiii
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(Original post by Sir Cumference)
So I'm guessing that the options you've posted here are incorrect and meant for another question?
They are the same as in the picture
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Soohiiii
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(Original post by mqb2766)
So how long is each side and what are the angles?
It’s whatever is on the picture
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mqb2766
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(Original post by Soohiiii)
It’s whatever is on the picture
Ok, I'll drop out here.
You should try and put a bit of effort into answering these questions. They're meant to help you learn.
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Sir Cumference
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(Original post by Soohiiii)
They are the same as in the picture
No they're different. This is what you posted:

Options:
- (root 2)(6-(root 2))
- 6(4-(root 2))
- 6(root 2)
- 2(6-(root 2))
- (root 2)(4-(root 2))
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Sir Cumference
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(Original post by Soohiiii)
It’s whatever is on the picture
Ok just looking at your image and ignoring everything else:

Can you please tell use what you think the angles in the triangle are since it's equilateral?
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Txeded
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1/2 × ab × sin60=1/2 × X^2 × (root3/2)= root3/4 × X^2 which is B
Last edited by Txeded; 3 weeks ago
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Soohiiii
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#20
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(Original post by mqb2766)
Ok, I'll drop out here.
You should try and put a bit of effort into answering these questions. They're meant to help you learn.
I have tried and now I am stuck hence why I am asking
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