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cjemistry/stoichiometry

what will be the mass of aluminum chloride produced by 20grams of aluminum carbonate, in the reaction of (aluminum carbonate + hydrochloric acid)?

Reply 1

Adambrl

Firstly you'd write out a balanced chemical equation for the reaction:
6HCl (aq) + Al2 (CO3)3 (s) --> 3H2O (l) + 3CO2 (g) + 2AlCl3 (aq)

Secondly you work out the moles of your limiting reagent:
n(Al2(CO3)3) = mass/mr = 20/234 (rounded to the nearest whole number) = 0.08547009 mol

Thirdly look at the reaction ratios of the limiting reactant and the desired product and multiply the moles accordingly:
since it's in a 1:2 ratio you double the moles = 0.17094018 mol

Finally find the mass of AlCl3 by rearranging the number of moles formula to get mass:
n=m/mr so to make m the subject = mr x n

133 x 0.17094018 = 22.7350439 or 22.7 grams.

so the theoretical mass of AlCl3 would be 22.7 grams. Hope this helps!