Vectors a level question

Can you post your working?

Right method, but I think the 2 from the 2AC applies for 2 x the direction vector AC rather than just for C

Not sure where you got +6 from when comparing the r coordinate

Right method, but I think the 2 from the 2AC applies for 2 x the direction vector AC rather than just for C

so should it be what I wrote out first?
I wrote 2q+q= 20+2, my numbers were just. rlly weird tho!!

so should it be what I wrote out first?
I wrote 2q+q= 20+2, my numbers were just. rlly weird tho!!

Your numbers are weird because you haven’t used the 2 for both of your initial workings.
Both sets of coordinates on the left hand side should be multiplied by 2-not just the first.

Work out the direction vector for AC then multiply by 2 for the 2AC - then work your method like you did before until you get 3q=... etc. and divide by 3 to get q

Thankyou to both of you!! I was just making such silly errors when writing the numbers down and I did what you both said and I have got it know thanks so much!!

this is what I got this time

Perfect!!! Well done

Thankyou to both of you!! I was just making such silly errors when writing the numbers down and I did what you both said and I have got it know thanks so much!!

this is what I got this time

If you aren't too busy do you think you could help me with this question!
(I've just posted the question and what I have tried to do)

Do you have the answer for this, not sure if I’ve done it right but don’t want to tell you the wrong thing!

If you aren't too busy do you think you could help me with this question!
(I've just posted the question and what I have tried to do)

If you aren't too busy do you think you could help me with this question!
(I've just posted the question and what I have tried to do)

You've found $\vec{AB}$ and its length. $\vec{AC}$ is in the same direction but has length 77. So you just need to scale $\vec{AB}$ so as to make it have length 77. (Which should be easy now if you have the length).

(And finally, don't forget to add A and $\vec{AC}$ to get the actual position of C).

You've found $\vec{AB}$ and its length. $\vec{AC}$ is in the same direction but has length 77. So you just need to scale $\vec{AB}$ so as to make it have length 77. (Which should be easy now if you have the length).

(And finally, don't forget to add A and $\vec{AC}$ to get the actual position of C).

I just tried it I tried to make the cs x y and z and im just a bit puzzled what step I should be doing

Have you found |AB| ?