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Mathis - Indices Help

Could anyone help answer the following with also providing the steps to get to the answer??
Thank you xx

Evaluate the following;
1- (5)(3y^0)

2-
(2^2)^2 x (3^3)^2
------------------------------
(2 x 3)^4
Reply 1
Any ideas? Theyre just about applying the exponent rules
https://www.mathsisfun.com/algebra/exponent-laws.html
Reply 2
Original post by mqb2766
Any ideas? Theyre just about applying the exponent rules
https://www.mathsisfun.com/algebra/exponent-laws.html

So would...

1 = 15
2 = 6^4
??
Reply 3
Original post by IonaNa
So would...

1 = 15
2 = 6^4
??

Any working?
1) yes
2) how do you apply the laws?
Original post by IonaNa
So would...

1 = 15
2 = 6^4
??

The word 'evaluate' means 'find the value of' so the answer will be a number.
Reply 5
Original post by Muttley79
The word 'evaluate' means 'find the value of' so the answer will be a number.


Original post by mqb2766
Any working?
1) yes
2) how do you apply the laws?

Okay so, 6^4 = 1296
Reply 6
Original post by IonaNa
Okay so, 6^4 = 1296

It's not correct. Can you explain your working?
Original post by IonaNa
Okay so, 6^4 = 1296

(2^2)^2 x (3^3)^2
------------------------------
(2 x 3)^4

so can you explain the steps you took?
Reply 8
Original post by Muttley79
(2^2)^2 x (3^3)^2
------------------------------
(2 x 3)^4

so can you explain the steps you took?

Well first i would simplify

(2^2)3^3 to 2^2 x 3 to 2^6
(3^3)^2 to 3^3 x 2 to 3^6
and then
(2 x 3)^4 to 2^4 x 3^4

so then i'll have
2^6 x 3^6
-------------
2^4 x 3^4

and that would be

6^12
-----
6^8

so

6^4??
Reply 9
Original post by mqb2766
It's not correct. Can you explain your working?

Well first i would simplify

(2^2)3^3 to 2^2 x 3 to 2^6

(3^3)^2 to 3^3 x 2 to 3^6

and then

(2 x 3)^4 to 2^4 x 3^4

so then i'll have

2^6 x 3^6
-------------
2^4 x 3^4

and that would be

6^12
-----
6^8

so then it would be 6^4 then i just put it into th calculator and got 1296??
Original post by IonaNa
Well first i would simplify

(2^2)3^3 to 2^2 x 3 to 2^6

(3^3)^2 to 3^3 x 2 to 3^6

and then

(2 x 3)^4 to 2^4 x 3^4

so then i'll have

2^6 x 3^6
-------------
2^4 x 3^4

and that would be

6^12
-----
6^8

so then it would be 6^4 then i just put it into th calculator and got 1296??

The numerator is

2^(2*2) * 3^(2*3)

Are you happy with that? Bidmas/bodmas is exponents before multiplication.
(edited 3 years ago)
Original post by IonaNa
Well first i would simplify

(2^2)3^3 to 2^2 x 3 to 2^6


No - you are misinterpreting the rules of indices here.

(2^2)^2 x (3^3)^2
------------------------------
(2 x 3)^4


There are a number of ways of tackling this - maybe think about multiply the numbers in brackets first?

(4)^ 2 x (9 ^ 2)
-------------------
(6)^4

Now to stop getting large numbers write out the factors

4 x 4 x 9 x 9
----------------
6 x 6 x 6 x 6

Does that help?
Reply 12
Original post by Muttley79
No - you are misinterpreting the rules of indices here.

(2^2)^2 x (3^3)^2
------------------------------
(2 x 3)^4


There are a number of ways of tackling this - maybe think about multiply the numbers in brackets first?

(4)^ 2 x (9 ^ 2)
-------------------
(6)^4

Now to stop getting large numbers write out the factors

4 x 4 x 9 x 9
----------------
6 x 6 x 6 x 6

Does that help?

I see i get it now
Thank you
Reply 13
Original post by mqb2766
The numerator is

2^(2*2) * 3^(2*3)

Are you happy with that? Bidmas/bodmas is exponents before multiplication.

Yes i understand it now,
Thank you, very helpful :smile:
Reply 14
Original post by IonaNa
Yes i understand it now,
Thank you, very helpful :smile:

So how would the answer look in full?
For these types of questions you can check your answer using your calculator.
Original post by IonaNa
So how would the answer look in full?

I thought you were ok with it, is there any confusion?
Reply 17
Original post by mqb2766
I thought you were ok with it, is there any confusion?

No, sorry i sent that by accident.
thank you for your help i do understand it :smile:

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