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I need help finding the second derivative !!!

the original curve was Y=lnx/x

I differentiated it to give me 1-lnx/x^2

could anyone give me some help with finding the second derivative?

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Original post by tdc453
the original curve was Y=lnx/x

I differentiated it to give me 1-lnx/x^2

could anyone give me some help with finding the second derivative?

Try it yourself and post what you get :smile:
Reply 2
Original post by Muttley79
Try it yourself and post what you get :smile:

I got d/dx(1-ln(x))times x^2-1(1-ln)) times d/dx(x^2) all over (x^2)^2

I don't know if this is right so far

and not too sure how I would even simplify

thanks :smile:
Original post by tdc453
I got d/dx(1-ln(x))times x^2-1(1-ln)) times d/dx(x^2) all over (x^2)^2

I don't know if this is right so far

and not too sure how I would even simplify

thanks :smile:

Hard to follow that - could you upload a photo of your working?
Reply 4
Original post by Muttley79
Hard to follow that - could you upload a photo of your working?

unfortunately I can't take a photo, but basically on paper I did as if I was differentiating normally using quotient rule.
Original post by tdc453
unfortunately I can't take a photo, but basically on paper I did as if I was differentiating normally using quotient rule.


That should be right
Original post by tdc453
I got d/dx(1-ln(x))times x^2-1(1-ln)) times d/dx(x^2) all over (x^2)^2

I don't know if this is right so far

and not too sure how I would even simplify

thanks :smile:


wait, rewrite your answer again
Original post by tdc453
unfortunately I can't take a photo, but basically on paper I did as if I was differentiating normally using quotient rule.

Could you put some brackets in it? The (x) is missing after ln ...

What is the question you are trying to answer?
Reply 8
Original post by CaptainDuckie
wait, rewrite your answer again

(d/dx(1-lnx))x^2-d/dx(x^2)(1-ln⁡(x)))/(2!(x^2)^2)
Original post by Muttley79
Could you put some brackets in it? The (x) is missing after ln ...

What is the question you are trying to answer?


They’re trying to find second derivative of lnx/x
Reply 10
Original post by tdc453
(d/dx(1-lnx))x^2-d/dx(x^2)(1-ln⁡(x)))/(2!(x^2)^2)

sorry ignore that
Reply 11
d/dx(1-lnx))x^2-d/dx(x^2)(1-ln⁡(x))/(x^2)^2
Original post by CaptainDuckie
They’re trying to find second derivative of lnx/x

I know that's what they said but it might not be what the question requires :smile:
Original post by Muttley79
I know that's what they said but it might not be what the question requires :smile:


It’s not impossible...
Original post by tdc453
d/dx(1-lnx))x^2-d/dx(x^2)(1-ln⁡(x))/(x^2)^2


Ohhhh, that’s right, my bad

You just haven’t simplified. Simplify it without the d/dx, it was confusing to read
(edited 3 years ago)
Original post by CaptainDuckie
It’s not impossible...

I know but frequently we get asked things that aren't what the question required.
Original post by Muttley79
I know but frequently we get asked things that aren't what the question required.


I see, I didn’t know :smile: thanks. This is probably a worksheet question (?) idk
Reply 18
could u guys help me with just the first line, I think I need a simpler start because idk where to go from here?
Original post by tdc453
could u guys help me with just the first line, I think I need a simpler start because idk where to go from here?


Simplify each of them, so for the (1 - lnx) what’s the derivative of that? Then times it by x^2, and so on.

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