A vessel and its contents of total heat capacity 120 J K–1 were heated using a methane burner. Calculate the maximum theoretical temperature rise when 0.10 g of methane was completely burned. The standard enthalpy of combustion of methane is
–890 kJ mol–1.
answer
moles methane = = 6.25 × 10–3 (1)
kJ evolved = 6.25 × 10–3 × 890 = 5.56 (1)
5.56 × 103 joules = (mc)T (1)
T = = 46.4 K (1)
I'm completely confused, could someone explain this to me? Thank you.