A2 Exponentials help

In a functions question, I got two functions equal 3^(X-2) and 3^(X) -2
For the last part I need to solve them, so
3^(x-2)=3^(x)-2

In the form ln(a)/ln(b)

I've tried the log laws many times but can't get an answer - can someone show me how please? Thanks

LHS is the same as $3^x \cdot 3^{-2}$ ... ie $\dfrac{3^x}{9}$.

Rearrange for 3^x before taking logs.