A typical sample of limestone contains 95.0% by mass of calcium carbonate, CaCO3. Fertiliser Z, Ca5NH4(NO3)11•10H2O (Mr = 1080.5gmol–1) can be made from limestone. Calculate the mass, in g, of limestone needed to make 1.50 kg of fertiliser Z. Give your answer to 3 significant figures.
1. Work out moles of fertiliser needed 2. Moles of calcium 3. Work out moles of calcium carbonate to contain moles of calcium. 4. Convert to mass of calcium carbonate 5. / 95. *100
Brev work it out please I can’t seem to get it Brev work it out please I can’t seem to get it (Original post by Old man1234)1. Work out moles of fertiliser needed 2. Moles of calcium 3. Work out moles of calcium carbonate to contain moles of calcium. 4. Convert to mass of calcium carbonate 5. / 95. *100
Why do we divide it by 95 and times it by 100 to get the whole mass of limestone. I don’t get it
The answer to my step 3 gives the mass of calcium carbonate needed. 95 % of limestone is calcium carbonate so divide by 95 x 100 to get 100% mass of limestone needed.
The answer to my step 3 gives the mass of calcium carbonate needed. 95 % of limestone is calcium carbonate so divide by 95 x 100 to get 100% mass of limestone needed.