Can someone please explain how this is a redox reaction in terms of oxidation states ?
CuO + 2HCl —> CuCl2 + H2O
The Oxygen in the CuO has oxidation state of -2. In H2O, oxygen was oxidised and has an oxidation no. of 0. The Hydrogen in HCl has oxidation state of +1. In H2O, hydrogen was reduced and has oxidation no. of 0. If you're wondering why 0, water is a liquid
The Oxygen in the CuO has oxidation state of -2. In H2O, oxygen was oxidised and has an oxidation no. of 0. The Hydrogen in HCl has oxidation state of +1. In H2O, hydrogen was reduced and has oxidation no. of 0. If you're wondering why 0, water is a liquid
The Oxygen in the CuO has oxidation state of -2. In H2O, oxygen was oxidised and has an oxidation no. of 0. The Hydrogen in HCl has oxidation state of +1. In H2O, hydrogen was reduced and has oxidation no. of 0. If you're wondering why 0, water is a liquid
Where are you getting these oxidation numbers from? In H2O, the oxidation number of oxygen is still -2. The hydrogen's oxidation number is also +1. There is no redox reaction, as Pigster has rightly said.
It is not redox. There are no changes to any of the oxidation numbers of any of the elements.
Oh okay. That is what I originally thought but it came up in a multiple choice question: Which reaction does NOT represent a redox reaction?
I selected that equation but it turned out to be wrong and I was confused about how it would be a redox reaction. Guess it was just a mistake in the question then. Thanks!