Maths Question Square Help

Hello I am stuck on how to fully answer this question (attached pdf / screenshot below).

The questions says the length of the sides of the outermost square are 4. So I used pythagoras theorem to calculate the length of the second largest square, 2^2 + 2^2 = 8, and √ 8 = 2√ 2, which is the length of the second largest square.

However, I'm now stuck on how to calculate the length of the third largest square and subsequently the smallest one. Any guidance would be appreciated, thanks

Hello I am stuck on how to fully answer this question (attached pdf / screenshot below).

The questions says the length of the sides of the outermost square are 4. So I used pythagoras theorem to calculate the length of the second largest square, 2^2 + 2^2 = 8, and √ 8 = 2√ 2, which is the length of the second largest square.

So for the total length of all of the sides so far I have 4(4) + 4(2√2) which is 16 + 8√2

However, I'm now stuck on how to calculate the length of the third largest square and subsequently the smallest one. Any guidance would be appreciated, thanks

Its worth noting that while you can use pythagoras 3 times, you should notice a relationhip(s) for the area/lengths? Id guess the question would expect you to have spotted the relationship(s), so if youre unsure, just post what you did/thought.

Thanks, I think I figured it out now!
The relationship or scale factor (?) between the length of the first two sides is 4 / 2√ 2 = √2, therefore I divided by √2 to find the length of the second smallest and smallest lengths. So, 2√2 / √2 = 2, and 2 / √2 = √2.
Therefore the total length of all sides if 4(4) + 4( 2√2) + 4 (2) + 4 (√2) = 16 + 8√2 + 8 + 4√2 which simplifies to 24 + 12√2.