If you look at the method, what the student is doing is heating a saturated solution of the salt until it is dry.
If you tried to dry hydrated copper sulphate by heating, what would happen to the water of crystallisation (i.e the water molecules in the crystal structure that make the copper sulphate hydrated)?
If you look at the method, what the student is doing is heating a saturated solution of the salt until it is dry.
If you tried to dry hydrated copper sulphate by heating, what would happen to the water of crystallisation (i.e the water molecules in the crystal structure that make the copper sulphate hydrated)?
Would they break? But I don’t really understand the difference between the two? In both cases isn’t water being evaporated and leaving a dry substance, like anhydrous copper (II) sulfate?
Would they break? But I don’t really understand the difference between the two? In both cases isn’t water being evaporated and leaving a dry substance, like anhydrous copper (II) sulfate?
The point of the experiment is to find the mass of the solute dissolved in the experiment.
The problem is that in the second case, some water actually forms part of the mass of the solute and in removing it by heating, you aren’t actually finding the mass of the solute because the water molecules that were part of the structure that get driven off account for some of the solute’s mass.
The point of the experiment is to find the mass of the solute dissolved in the experiment.
The problem is that in the second case, some water actually forms part of the mass of the solute and in removing it by heating, you aren’t actually finding the mass of the solute because the water molecules that were part of the structure that get driven off account for some of the solute’s mass.