GCSE Maths Help

Can someone help me with this question - I can't seem to get it

x = 1/(2^183 * 5^180)

Show that when x is written as a terminating decimal there are 180 zeros after the decimal point.

Original post by Anonymous

Can someone help me with this question - I can't seem to get it

x = 1/(2^183 * 5^180)

Show that when x is written as a terminating decimal there are 180 zeros after the decimal point.

No need to post as anonymous, but think about 1/(2*5) is.

OP

Ty for the reply but I still don't get it

Original post by mqb2766

No need to post as anonymous, but think about 1/(2*5) is.

Original post by Anonymous

Ty for the reply but I still don't get it

You cant work out what 1/(2*5) is as a decimal?
Or 1/(2^2 * 5^2) or ...?
Just put in your calculator if necessary to spot / understand the pattern.

OP

Original post by mqb2766

You cant work out what 1/(2*5) is as a decimal?
Or 1/(2^2 * 5^2) or ...?
Just put in your calculator if necessary to spot / understand the pattern.

Yes I understand that far and I understand the pattern but I don't know how to go about the fact that the bases have different powers

Original post by Anonymous

Yes I understand that far and I understand the pattern but I don't know how to go about the fact that the bases have different powers

It helps to post what youve done/understand. The question asks for 180 leading zeros, so how many 2s and 5s will that need, what is left over ...

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