Original post by francomanco2309
how do you rationalise this denominator?
1/1+root3
1/1+root3
what have you tried?
Original post by Muttley79
what have you tried?
yes thats what i did, i multiplied the top and bottom by1-root3. I got the top part right but the bottom part wrong and i tried so many times idk where i went wrong
Original post by francomanco2309
yes thats what i did, i multiplied the top and bottom by1-root3. I got the top part right but the bottom part wrong and i tried so many times idk where i went wrong
It should be simple difference of two squares, so what did you do for the denominator?
(edited 7 months ago)
Original post by mqb2766
It should be simple difference of two squares, so what did you do for the denominator?
I done 1-root3 +root3 -root9
So, i simplified that to 1-root9 for the denominator.
however the answer says that the denominator is 2 or -2
Original post by francomanco2309
I done 1-root3 +root3 -root9
So, i simplified that to 1-root9 for the denominator.
however the answer says that the denominator is 2 or -2
So, i simplified that to 1-root9 for the denominator.
however the answer says that the denominator is 2 or -2
and the square root of 9 is ...
Note it would be slightly simpler to treat the denominator as
sqrt(3)+1
and multiply top and bottom by
sqrt(3)-1
keeps things a bit simpler but the overall result is obviously the same.
(edited 7 months ago)
Original post by mqb2766
and the square root of 9 is ...
Note it would be slightly simpler to treat the denominator as
sqrt(3)+1
and multiply top and bottom by
sqrt(3)-1
keeps things a bit simpler but the overall result is obviously the same.
Note it would be slightly simpler to treat the denominator as
sqrt(3)+1
and multiply top and bottom by
sqrt(3)-1
keeps things a bit simpler but the overall result is obviously the same.
Ohh i see thankyou so much for clearing this up for me
Original post by francomanco2309
yes thats what i did, i multiplied the top and bottom by1-root3. I got the top part right but the bottom part wrong and i tried so many times idk where i went wrong
So your denominator went wrong in your multiplication? in terms of that you can use the third binomial formula: (1 - root3) * (1 + root3). Multiply this formula out in the denominator to the end and (1 + root3) in numerator and everything should get be fine.
EDIT: just see that you already got an answer to this, my bad! if you got it, the fraction is 1 * ( 1 + root 3) / -2 or 0.5 * (1 + root 3).
(edited 7 months ago)
Original post by francomanco2309
I done 1-root3 +root3 -root9
So, i simplified that to 1-root9 for the denominator.
however the answer says that the denominator is 2 or -2
So, i simplified that to 1-root9 for the denominator.
however the answer says that the denominator is 2 or -2
you've overcomplicated things by saying that , but overlooked the fact that the definition of is that
Original post by francomanco2309
how do you rationalise this denominator?
1/1+root3
1/1+root3
1/(1+root3) x (1-root3)/(1-root3) = (1-root3)/(1+root3)(1-root3) = (1-root3)/(1-root3+root3-3) = (1-root3)/-2 = (root3-1)/2
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