https://postimg.cc/pmw3kyj5

The ans is D but Im confused on how to solve it, mainly due to the position of the cosine

The ans is D but Im confused on how to solve it, mainly due to the position of the cosine

Original post by MonoAno555

https://postimg.cc/pmw3kyj5

The ans is D but Im confused on how to solve it, mainly due to the position of the cosine

The ans is D but Im confused on how to solve it, mainly due to the position of the cosine

Post what you've tried as per forum rules

Original post by MonoAno555

https://postimg.cc/pmw3kyj5

The ans is D but Im confused on how to solve it, mainly due to the position of the cosine

The ans is D but Im confused on how to solve it, mainly due to the position of the cosine

Not sure what you mean by the position of the cosine, but the trig term is

cos(2pi/lambda(x-vt))

so acceleration is the usual second derivative wrt time. Then a bit of simple reasoning to get the maximum value.

(edited 1 year ago)

Original post by mqb2766

Not sure what you mean by the position of the cosine, but the trig term is

cos(2pi/lambda(x-vt))

cos(2pi/lambda(x-vt))

Oh I understand it now because of the brackets you put!. it isn't written like that in the book so I thought it meant s(x,t) = 2pi/lambda(cos(x-vt)). i will try it again, thank you

Original post by mqb2766

Not sure what you mean by the position of the cosine, but the trig term is

cos(2pi/lambda(x-vt))

so acceleration is the usual second derivative wrt time. Then a bit of simple reasoning to get the maximum value.

cos(2pi/lambda(x-vt))

so acceleration is the usual second derivative wrt time. Then a bit of simple reasoning to get the maximum value.

That's exactly why I asked them to post what they'd done ...

Original post by MonoAno555

Oh I understand it now because of the brackets you put!. it isn't written like that in the book so I thought it meant s(x,t) = 2pi/lambda(cos(x-vt)). i will try it again, thank you

Thinking about the coefficient of t inside the cos term, the answer is fairly straightfoward.

While the argument may look a bit strange,the v/lambda = frequency (Hz) and the 2pi (and t) maps it to radians. So it does make sense. x-vt would not be in radians.

https://www.desmos.com/calculator/bjt6dleg5h

from

https://www.physicsforums.com/threads/what-exactly-does-x-vt-mean-in-the-wave-equation.836348/

is a decent picture to have inside your head.

(edited 1 year ago)

- How hard is Aqa a- level maths?
- A level integration help
- Solve this set of parametric equations in terms of t using just trig identities
- SHM
- Arm Software Engineer Level 6 Degree Apprenticeship 2024 - DTS BSc
- Calculators in Cambridge A levels
- Maths
- A level maths trigonometry question
- Trigonometric differentiation question
- Econ+Maths joint honours, or straight Econ?
- Intergrate
- Numbers of Arrangements
- Mechanics flagpole question
- Maths yr2 trig help
- Do you think A Level Maths has enough proof in it?
- Advanced mathematics
- A level trigonometric proof question
- Tips for AS maths
- Maths vs Maths and Physics
- Calculators in Cambridge Alevels

Latest

Trending

Last reply 1 week ago

can someone please explain what principle domain is and why the answer is a not c?Maths

0

13