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Exponential growth/decay

I have come up with answers for the two below questions but not 100% sure they are correct:

y = (5-2e^3t)dt time is between 2 and 4 seconds

y = (e^-7t) dt time is between 0 and 5 seconds

Answer for the first question:
10 + 2/3 (e^3t) = 9.998

Answer for the second question:
1/7 - e^35/7 = 0.142857

Thanks!
Reply 1
Original post by thomas0611
I have come up with answers for the two below questions but not 100% sure they are correct:

y = (5-2e^3t)dt time is between 2 and 4 seconds

y = (e^-7t) dt time is between 0 and 5 seconds

Answer for the first question:
10 + 2/3 (e^3t) = 9.998

Answer for the second question:
1/7 - e^35/7 = 0.142857

Thanks!

Agree with the second, though the first looks wrong assuming the exponential is e^(3t)
Reply 2
Original post by mqb2766
Agree with the second, though the first looks wrong assuming the exponential is e^(3t)

Sorry the second one should have a minus sign so should read (5-2e^(-3t)), that should hopefully give the answer 9.998
Reply 3
Original post by thomas0611
Sorry the second one should have a minus sign so should read (5-2e^(-3t)), that should hopefully give the answer 9.998

Agreed. Strange question as the exponential term is ~0 over the range youre integrating over but ...
Reply 4
THANKS

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