Firstly, calculate the number of moles of Aluminium Sulphate you'd have. Then, since it dissociates and the SO4 ions are all we are interested in, calculate how many moles of those there would be in the solution (by the ratio of those to aluminium in the compound). Finally, convert from moles to number of molecules by times the number of moles by avagadro's number.
ok, that would give me 0.075 moles of sulphate ions Multiply this by Avogardos constant is 4.515x10 to the power 23
and this isn't the correct answer, 9x10 to the power 22?
ah yes, sorry - charco is right. There's 3 SO4 molecules in Al2SO4 so there's 3 moles of SO4 per mole of Al2SO4 - just times the number of moles by 3, not by 3 halves.
Sorry. just trying to get my head around this... Al2(SO4)3 Shows two aluminium ions for every three sulphate ions Hence, every 1 formula unit contains two aluminium ions and three sulphate ions.
Sorry. just trying to get my head around this... Al2(SO4)3 Shows two aluminium ions for every three sulphate ions Hence, every 1 formula unit contains two aluminium ions and three sulphate ions.