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OCR MEI AS Mathematics Core 1 13/05/2013

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Reply 40
Original post by Dan_JR_12
It could have 2 tangents, depending on the value of k, because it was a reciprocal graph. It had to different curves


Ah yes! May not be as wrong as I thought then :smile: Hopefully I got one of them right.
Original post by rach100
yhh same, but i ended up with surds for most of them :/


Same - really annoying but I'm sure we did it the right way


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Reply 42
Yeah I got that for the 125 root 5 question :smile:
Original post by jo7777
I used the quadratic formula three times I think :smile:
For the 125 root 5 question did you get 5^7/2?


Spot on


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Reply 44
What did anyone get for question 9? and for question 10 what was people intersecting circles?
Reply 45
what did you guys get for the minimum value of y?
Can I have a prediction of the grade boundaries for an A btw ?


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Original post by Sun_Bear
what did you guys get for the minimum value of y?


-7


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Reply 48
question nine anyone?
Reply 49
Original post by hayjohn30
What did anyone get for question 9? and for question 10 what was people intersecting circles?

Which one was question 9?
Reply 50
Someone create an unofficial mark scheme to with predicted grade boundaries?
Reply 51
Original post by Dan_JR_12
Which one was question 9?


The divisible by 3? I ended up from the sum as 3x^2+2
Reply 52
What did people get for the coefficient of x^3 in the binomial expansion question?
I got that but did you divide it by 3 as means of explaining you couldn't fully divide it by 3 ?


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Reply 54
I reckon it will be about 55-58 for an A i thought the paper was quite easy apart from the last question
Q 12 is where most candidates will loose loads of marks
Reply 55
I think I got everything right apart from retardedly writing 8a^8 instead of 8a^9...

last question was k=0 or 4, by discriminant = 0

distance between chord and centre was root10

on one of them the y intercepts (I think) were 2+root11 and 2-root11

cant remember much else
Original post by Dan_JR_12
What did people get for the coefficient of x^3 in the binomial expansion question?


-2560 but i think I've put positive 2560 :frown:


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Reply 57
I got k as 0 and 12. The tried verifying the values k by subbing it back in the quadratic. Was 9 the proof if so I got 3n for the first one and said that 3 can be taken out. And the 9 part 2 I got 3n^2+2 and said 3 couldn't be removed. Not sure about part 2 though. I got (2,-7) as min point
Reply 58
Original post by krishkmistry
I got that but did you divide it by 3 as means of explaining you couldn't fully divide it by 3 ?


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Yeh eventually and for the coefficient i got it wrong but it was 10 x 4 x -64x^3
Reply 59
coefficient was -2560

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