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The Physics PHYA2 thread! 5th June 2013

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Original post by SortYourLife
The mechanics? I love that bit ! It's waves I struggle with, but then again I loved the teacher I had for mechanics and hated the one I had for waves and optics and everything when I learnt it the first time round


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I love the waves.
I have the same teacher for all so i can't blame the teacher and i wouldn't want to because he's amazing :awesome:
I just don't like mechanics.

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Was just looking on the January 2013 thread for this exam, just to see if there was any useful materials posted, someone posted some good last minute notes on the breakdown of each topic which was good, enjoy:

Mechanics:
1. The calculations are really easy IMO, just use SUVAT for most calculations :smile:
2. You need to be able to understand the graphs, which is pretty much common sense.
3. Know about Newton's laws, F=ma, every force has an equal an opposite force acting on it when the object is in equilibrium
4. Conservation of energy - really easy, basically max p.e. and min k.e. at top and max k.e. and min p.e. at the bottom. Why isn't all p.e. converted into k.e. when something is dropped in real life? because of energy being transferred to heat energy because of air resistance/ friction etc.
5. Definition and principle of a moment:
Definition = force x perpendicular distance from the pivot
Principle = sum of anticlockwise moment + sum of clockwise moment = 0
Think that's it really for mech...

Materials:
1. The practicals: obviously this depends on the practical that you are given but it's pretty much a summary of what you know and most of them award marks for the same things. One or two mentions for all the following should ensure at the very least half the marks. Reliability, Accuracy (like in fringe spacing, you would say increase D, perform in dark room, etc) maybe one for safety (like wear LASER goggles when using a laser, warn people not to look directly into the laser) Whenever you mention a measurement don't forget to mention a measuring instrument (vernier calliper for springs, wires, etc. *not sure* micrometer for fringe spacing?*not sure*. Also, don't forget to mention a graph and a table (maybe it helps to draw out the table yourself in pencil in a little corner so you know all the things that you need to do). I think that should cover it really for practicals.
2.Know Hooke's law: F=k[delta]L up to the limit of proportionality NOT the elastic limit as the elastic limit may sometimes come before the limit of proportionality.
3. Don't forget when making calculations from the graph to remember that it's in standard form.

Waves:
Possibly the hardest part of the course IMO but nothing too drastic
1. Be aware of the different types of waves but don't go mental over it, it's very rare that they ask you about the different types like mechanical, seismic etc. and if it does come up it's likely to only be 1 mark. However do be aware of transverse and Longitudinal waves. Transverse have direction of vibration perpendicular to direction of motion, Longitudinal have direction of vibration paralell to direction of motion. Also, be aware that transverse waves can be polarised and all the stuff that comes with polarisation, how it happens, what it does, what happens if you rotate the 2nd filter 90/ 180 degrees.
2. Refractive index, snells law etc.
Ok so basically n1.sin(i)=n2.sin(r) when r= 90 i=critical angle
when i= critical angle the light ray refracts along the boundary,
when i>ic total internal reflection occurs (i=r)
when i more dense = slows down and bends towards the normal
more dense -> less dense is the opposite and remember to flip the refractive index equation i.e. 1/n = sin(r)/sin(i)
3. Optical fibres: Uses include can transport data more quickly, therefore greater broadband speed, uses in medicine etc.
Core is made as narrow as possible to reduce multipath dispersion as waves travel less distance, cladding is used to protect the core, to help cause total internal reflection by having a lower/ higher refractive index not sure which can't remember now but it can be worked out...
4. Stationary aves and the fundamental waves:
The formation of a stationary wave: a string clamped at each end produces two proggressive waves at each end with the same constant phase difference, frequency amplitude, wavelength, equal and opposite velocities and they superimpose at the centre.
Fundamental waves this is quite easy and usually a very small section, know for the first that wavelength=2xlength. Also, know how to calculate frequency which is bsically just the rearrangement of the wave speed equation
5. Diffraction: This is when light is shone through a number of slits and you get a diffraction pattern so this is d.sin(pheta)=n(lamder)
n is the order of the beam and be aware that max order occurs when pheta=90 deg and DON'T round up when giving the max order, if you get 2.8 then the max order is 2
d will usually be given as the number of slits per mm, therefore d= 1/(number of slits)x10^3
6. Two source intereference: This is mainly the use of w=(lamder)D/s
remember just like the previous equation you may have to use this equation in explanations to show certain things are proportional/ inversely proportional
Know about destructive and constructive intereference and how you get maxima/ minima
7. Monochromatic vs. White Light:
Monochromatic = single wavelength
Monochromatic gives a dark/ bright fringe pattern with the bright fringe beng the colour of the laser unlike in white light which has multiple wavelengths and has a central bright fringe with blue inner fringes (either side of the central maxima) then you have a rainbow(you don't have to mention the rainbow) then you have the red outer fringe





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Someone help in how to do moment calculations, don't just seem to get them :frown:


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Original post by Jimmy20002012
Someone help in how to do moment calculations, don't just seem to get them :frown:


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Anticlockwise moment = clockwise moment for a system in equilibrium.


Moment = force * perpendicular distance to line of action (given on formula sheet)

Tbh, I *think* on this one, all the forces tend to be perpendicular, however I could be wrong and you may need to use sin or cos to find the perpendicular force

So wherever your pivot is, look at EVERY force acting on it, and follow a circle round one way. Assuming you have all your forces labelled, take into account every arrow that points in the same direction your circle is going, then an equals sign, then the same again with the other way round


That probably makes no sense and is probably better explained with an example, but i feel it is too late for me to be doing that now :tongue: but if you would like an example I would be happy to do one :smile:


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Original post by SortYourLife
Anticlockwise moment = clockwise moment for a system in equilibrium.


Moment = force * perpendicular distance to line of action (given on formula sheet)

Tbh, I *think* on this one, all the forces tend to be perpendicular, however I could be wrong and you may need to use sin or cos to find the perpendicular force

So wherever your pivot is, look at EVERY force acting on it, and follow a circle round one way. Assuming you have all your forces labelled, take into account every arrow that points in the same direction your circle is going, then an equals sign, then the same again with the other way round


That probably makes no sense and is probably better explained with an example, but i feel it is too late for me to be doing that now :tongue: but if you would like an example I would be happy to do one :smile:


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That sort of helped, how about a question like this:

http://filestore.aqa.org.uk/subjects/AQA-PHYA2-W-QP-JUN10.PDF

1c and 1d?


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Original post by Jimmy20002012
That sort of helped, how about a question like this:

http://filestore.aqa.org.uk/subjects/AQA-PHYA2-W-QP-JUN10.PDF

1c and 1d?


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1b.jpg
1c.jpg
1d.jpg


i know you didnt ask for 1b, but thought id include it as it has moments :smile:
hope i've helped!
Original post by SortYourLife
1b.jpg
1c.jpg
1d.jpg


i know you didnt ask for 1b, but thought id include it as it has moments :smile:
hope i've helped!


I know it late :smile:

Think you might have done the first question wrong, it says find the moment of the bikers weight so it would be Moment= f x d= 780 x 0.35 = 273Nm.

For the second part, just few questions why do you ignore force Y and what do you mean by the furthest right?

Think you have made me sort of understand moments now, thanks soo much :smile:


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Original post by Jimmy20002012
I know it late :smile:

Think you might have done the first question wrong, it says find the moment of the bikers weight so it would be Moment= f x d= 780 x 0.35 = 273Nm.

For the second part, just few questions why do you ignore force Y and what do you mean by the furthest right?

Think you have made me sort of understand moments now, thanks soo much :smile:


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Ah yeah I did! Sorry!


You ignore force Y as you're taking moments about point B, force Y is on point B, therefore your distance from the pivot is 0, giving you a moment of 0 (as 0* anything = 0) and so can be ignored


I just meant you're pivots at the end, so it ends up being up= down, as when some the pivots in the middle so like if you had an upwards force on each side of the pivot, one would be clockwise and one would be anticlockwise


And no worries, I hope I've helped aha!


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Original post by SortYourLife
Ah yeah I did! Sorry!


You ignore force Y as you're taking moments about point B, force Y is on point B, therefore your distance from the pivot is 0, giving you a moment of 0 (as 0* anything = 0) and so can be ignored


I just meant you're pivots at the end, so it ends up being up= down, as when some the pivots in the middle so like if you had an upwards force on each side of the pivot, one would be clockwise and one would be anticlockwise


And no worries, I hope I've helped aha!


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Thanks soo much, I actually get and can do moment calculations now, thanks again :biggrin:


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What's the six marker predicted on?

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Original post by UnknownGuy
What's the six marker predicted on?

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Hopefully it's something like young modulus, but they may ask something to do with mechanics :smile:


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I'm having a pure guess but I reckon the 6 marker might be to with the electromagnetic spectrum... or projectiles. Since neither of those have ever come up and you could probably talk a lot about them. But I doubt it will be on Hooke's Law as that has appeared twice. My bet is projectiles. :cool:
Reply 112
Original post by x-Sophie-x
I think pretty much the same.

Does anyone know if we need to know Electron Diffraction in depth?
I've heard different things about the level of detail I need to know.


Electron Diffraction or Wave Diffraction?
Reply 113
Original post by Caramelapps
I'm having a pure guess but I reckon the 6 marker might be to with the electromagnetic spectrum... or projectiles. Since neither of those have ever come up and you could probably talk a lot about them. But I doubt it will be on Hooke's Law as that has appeared twice. My bet is projectiles. :cool:


How can you have 6 marker on Projectile?
Can someone help me with question 6a june 2010, you have to mark on the wavelength and d (wavelength=dsinx) on a diagram and I'm unsure what the answer is the mark scheme just says 'correct wavelength marked'??? thanks for the help in advance!
Reply 115
I don't get question 6a on the June 2010 paper. The mark scheme just says "lambda correct" and "d correct" but doesn't show you what to draw. Please could someone draw them on an upload it or explain it to me?? (I can't find them labelled in the similar diagram in the textbook) :frown:

http://filestore.aqa.org.uk/subjects/AQA-PHYA2-W-QP-JUN10.PDF

Mark scheme http://filestore.aqa.org.uk/subjects/AQA-PHYA2-W-MS-JUN10.PDF
Reply 116
Original post by lamp010101
Can someone help me with question 6a june 2010, you have to mark on the wavelength and d (wavelength=dsinx) on a diagram and I'm unsure what the answer is the mark scheme just says 'correct wavelength marked'??? thanks for the help in advance!


Lol! I think we've both come across the same question at exactly the same time!! I'm also unsure. :colondollar:
That's a bit of a coincidence! I wish there was a diagram in the mark scheme to show how it's done like there sometimes is... :smile:
Reply 118
what would you write for a 6 marker projectile, can you please post a model answer?
Reply 119
Original post by omnom
what would you write for a 6 marker projectile, can you please post a model answer?


I would write (this is it separated into points):

Acceleration of object equal to g (acceleration of free fall) and is downwards as gravity acts downwards

Acceleration only affects vertical motion of object

Horizontal velocity of object is constant

Acceleration does not have a horizontal component

The motions in the horizontal and vertical directions are independent of each other

For an object projected vertically:

v = u gt
s= ut (1/2)gt^2

For an object projected horizontally:

Vertical component of displacement = (1/2)gt^2
Horizontal component of displacement = horizontal velocity x t
Time taken to fall is independent of how fast object is projected

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