Just look at the diagram side ways and you know the bike handle is turning around the pivot so essentially the moment you worked out earlier = T x 25mm The handle being pushed down so it must be clockwise

Does this make sense or should I draw a diagram?

(edited 10 years ago)

Reply 213

Jimmy20002012

4

Original post by .raiden.

Just look at the diagram side ways and you know the bike handle is turning around the pivot so essentially the moment you worked out earlier = T x 25mm The handle being pushed down so it must be clockwise

Does this make sense or should I draw a diagram?

Oh, so the tension is basically anticlockwise? And with the question to do with the guy on the slope, why is the weight component sin not cos, or is it asking for the weight component actually down the slope? :smile:

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Reply 214

.raiden.

OP

10

Original post by Jimmy20002012

Oh, so the tension is basically anticlockwise? And with the question to do with the guy on the slope, why is the weight component sin not cos, or is it asking for the weight component actually down the slope? :smile:

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Yes it is, I drew a diagram.

Look at my earlier post explaining why its sin :smile:

I don't understand the stuff about pitch, frequency and note.

in the textbook, it says that 'the pitch of a note corresponds to frequency', so it seems to me that if two things had the same pitch, then that means they have the same frequency

so how is it that for a vibrating string tuned to the same pitch as a tuning fork, it can include all sorts of overtone frequencies whereas a tuning fork would only vibrate at the fundamental frequency?

Reply 216

MelisBaysal

Has anyone does Jan 10 past paper? i need help on question 2 a part 3 :frown:

its on moments...

Reply 217

anonymouse01

Yeah but there was already another thread. Anyway

Q3 jan 09 thanks

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Reply 218

lebron_23

2

Original post by MelisBaysal

Has anyone does Jan 10 past paper? i need help on question 2 a part 3 :frown:

its on moments...

Taking moments about B leaves you with two other figures, one which you know (the mass) and the other which you don't (A).

The mass of the truck is he clockwise moment and A is the anticlockwise moment. That gives you;

14000*1.4 = A*2.5

A = 7840

Then because there are two springs and each will exert the same force, you simply divide your answer by two giving you 3920.

Reply 219

MelisBaysal

Original post by lebron_23

Taking moments about B leaves you with two other figures, one which you know (the mass) and the other which you don't (A).

The mass of the truck is he clockwise moment and A is the anticlockwise moment. That gives you;

14000*1.4 = A*2.5

A = 7840

Then because there are two springs and each will exert the same force, you simply divide your answer by two giving you 3920.

ah ok but why use 2.5 why not the distance of the rear springs to the centre of mass?

The Physics PHYA2 thread! 5th June 2013

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