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how do you find the coordinates of the vertex in the equation x2​+10x+19?
Original post by MSB47
how do you find the coordinates of the vertex in the equation x2​+10x+19?

Either differentiate to find the turning point or complete the square.
Do you know how to differentiate, or have you not got to calculus yet?
(This might affect your approach to the question.)
Reply 3
Original post by placenta medicae talpae
Do you know how to differentiate, or have you not got to calculus yet?
(This might affect your approach to the question.)


i have just started calculus and been introduced to the dy/dx formula
Original post by MSB47
i have just started calculus and been introduced to the dy/dx formula


Cool: calculus will make this nice and simple for you :smile:

You want to find a point where your function, call it f, has gradient 0.
You can do this by differentiating f(x) and setting the result to equal 0.
This will happen at precisely one x-value (as is the case for any parabola).
So all you need to do is crunch the numbers :smile:
(edited 10 years ago)

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