prove that tan(6theta)=...............
Could somebody possibly help me with question 8b please?
Thanks
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(edited 9 years ago)
Original post by Mutleybm1996
I'm assuming you've made some progress? Post your working.
Original post by notnek
I'm assuming you've made some progress? Post your working.
The second image is as far as I've got in this case
Would i need to convert all of the cos's on the top into sin's and divide through by cos? or something along those lines?
Posted from TSR Mobile
Original post by Mutleybm1996
The second image is as far as I've got in this case
Would i need to convert all of the cos's on the top into sin's and divide through by cos? or something along those lines?
Posted from TSR Mobile
Would i need to convert all of the cos's on the top into sin's and divide through by cos? or something along those lines?
Posted from TSR Mobile
Sorry, I didn't see your second image. Try dividing top and bottom by
Original post by notnek
I'm assuming you've made some progress? Post your working.
like this?
Posted from TSR Mobile
Original post by notnek
Sorry, I didn't see your second image. Try dividing top and bottom by
here...i think...
Posted from TSR Mobile
Original post by notnek
Sorry, I didn't see your second image. Try dividing top and bottom by
sorted it!
thank you!
Posted from TSR Mobile
Original post by notnek
Sorry, I didn't see your second image. Try dividing top and bottom by
Can I quickly ask how to do part c? My calculator is not giving me exact values(it usually does!). I got (20-30(sqrt2))/23
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Original post by Mutleybm1996
Can I quickly ask how to do part c? My calculator is not giving me exact values(it usually does!). I got (20-30(sqrt2))/23
Posted from TSR Mobile
Posted from TSR Mobile
That's not correct. Can you post your working for this one?
sorted
moderator please close this thread
Posted from TSR Mobile
moderator please close this thread
Posted from TSR Mobile
Original post by Mutleybm1996
Yoi can set the thread to "answered" if you like. There's no need for the thread to be closed.
Quick Reply
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