M1 OCR (Not MEI) Exam - 9/06/2015

OP

Can anyone help with Q2 iii June 2007 please.

Reply 282

OP

Original post by Issy :)

Question 6ii? What is it even asking for, I thought P was on a horizontal surface so R=8N ??
http://static1.squarespace.com/static/52c1f91ee4b0a77a50337e61/t/54c7fbeae4b0012fe2a248eb/1422397464150/OCR+M1+June+2014.pdf

I did that exam :frown:

It was horrible!! :angry:

Reply 283

Original post by MsFahima

Can anyone help with Q2 iii June 2007 please.

I split it up into triangle, rectangle, two identical triangles. For first triangle, s = 1/2*40*12. Rectangle, s = (250-40)*12. As the last decelerating bit is constant, the place where it intersects the x axis must be halfway between 250 and 290 = 270. Therefore the first triangle there has s=1/2*12*(270-250) and the second one is identical, therefore you multiply that area by two. Adding all this together gets 3000m.

Reply 284

Original post by MsFahima

Can anyone help with Q2 iii June 2007 please.

The distance is just the area under the graph, as it is distance negative velocities do not affect it.

So you have a triangle, a rectangle, another two triangles, or just one rectangle.

So area = (40x12)/2 + (210x12) + (20x12) --> could have halved it and worked out the positive section and then did the same for the negative bit but they are the same area so just leave it as it is.
=3000m

Reply 285

Can someone explain jan 2011 5c.

Reply 286

OP

Original post by chloe-jessica

I split it up into triangle, rectangle, two identical triangles. For first triangle, s = 1/2*40*12. Rectangle, s = (250-40)*12. As the last decelerating bit is constant, the place where it intersects the x axis must be halfway between 250 and 290 = 270. Therefore the first triangle there has s=1/2*12*(270-250) and the second one is identical, therefore you multiply that area by two. Adding all this together gets 3000m.

I keep getting the wrong answer! And that's what I did.

Anyway, thank you!

Reply 287

Original post by Issy :)

Question 6ii? What is it even asking for, I thought P was on a horizontal surface so R=8N ??
http://static1.squarespace.com/static/52c1f91ee4b0a77a50337e61/t/54c7fbeae4b0012fe2a248eb/1422397464150/OCR+M1+June+2014.pdf

R does equal 8. However the contact force is the resultant of R and friction. Friction must be equal to the horizontal force for it to be in limiting equilibrium, therefore results is the square root of 8²+3² = 8.54N. Then use trig, if x=angle with horizontal, tanx= 8/3, x=69.4^o.

Reply 288

Issy :)

Can you please draw me a diagram?

Original post by chloe-jessica

R does equal 8. However the contact force is the resultant of R and friction. Friction must be equal to the horizontal force for it to be in limiting equilibrium, therefore results is the square root of 8²+3² = 8.54N. Then use trig, if x=angle with horizontal, tanx= 8/3, x=69.4^o.

Reply 289

OP

Original post by Super199

The distance is just the area under the graph, as it is distance negative velocities do not affect it.

So you have a triangle, a rectangle, another two triangles, or just one rectangle.

So area = (40x12)/2 + (210x12) + (20x12) --> could have halved it and worked out the positive section and then did the same for the negative bit but they are the same area so just leave it as it is.
=3000m

Thanks.

Reply 290

Original post by MsFahima

Thanks.

Help me either 5i from Jan 2011 or 7i pleaasssee.
Thanks :smile:

Reply 291

Original post by Super199

Help me either 5i from Jan 2011 or 7i pleaasssee.
Thanks :smile:

In fact I have done 7i. So 5i part c actually sorry.

:smile:

Reply 292

Shakzey

1

Original post by lauren_2

Probably sound completely clueless but what are they?!

the questions where theres a particle on top of a box on a surface for example and they are both moving at the same time. for example, June 2013 Q7.

Reply 293

Original post by Issy :)

Can you please draw me a diagram?

Reply 294

Anemone4Life

8

hopefully this helps, anything with a pulley can be turned in to sim equations with tension, accleration and weight which makes the question GCSE level maths and easy :tongue:

a link to a video explaining this :
https://www.youtube.com/watch?v=r73j4prNAug

(edited 8 years ago)

Reply 295

ChoccyPhilly

13

i love m1 but the issue is that you never really know you're right or wrong as the answers could be so different but still kind of make sense

Reply 296

Original post by Anemone4Life

hopefully this helps, anything with a pulley can be turned in to sim equations with tension, accleration and weight which makes the question GCSE level maths and easy :tongue:

Took me a good few seconds to figure out what sim equations were, thought I was doomed because I hadn't learnt them :facepalm:

Exams are muddling my brain.

Reply 297