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Original post by imedico10
i'll try my best... according to f(x) x must be bigger than zero.

the graph for fg is 3e^x +x^2 ..... is you sub x=0 you get y as 3.... after 3... y keeps increasing exponentially so the range (values of y) is bigger than 3. hope this helps :smile:

this image shows what im trying to say


Omg thaaaaaanks! :smile: so in these questions I just substitute the domain to find the range and draw a graph right?
Do you have to know how to derive the factor formulae? ExamSolutions didn't mention it in his factor formulae videos so I guess not but I just wanna make sure...
Original post by Gome44
X^2 + 3 is always positive anyway, so you can just remove the mod sign :smile:


Ok, what if it was:

|x^2 - 36| + 2x

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Original post by Medicjug
Someone pleaseeeeeee helpppp ImageUploadedByStudent Room1433887920.628872.jpg


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a) Use the double angle formula to expand Rcos(x-#) (pretending # is alpha):L

Rcos(x - #) ---> Rcosxcos# + Rsinxsin#

Take coefficients of cosx and sinx:

Rcos# = 1 and Rsin# = ROOT(3)

Since Rcos#/Rsin# ----> tan# (where R cancels out)

-> tan# = Root(3)/1

solve tan^-1(root(3)/1) to get your value for #. # = (pie)/3

To find R -----> R^2 = 1^2 + (root(3))^2
R = root(4) = 2
Leave in the form - 2cos(x - (pie)/3) where you have a value for # as (pie)/3

b) Use your values in part a) to solve b)! Very much like C2!!

Hope this helps!!
(edited 8 years ago)
Original post by it's a me, mario
Ok, what if it was:

|x^2 - 36| + 2x

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Doubt this will ever come up, but here's how I would do it:

Consider when the inside of the | | sign is negative. This is when -6<x<6. A property of the mod sign is |y| =-y when y<0. In this case y=x^2 -36. So from -6<x<6, the curve you need to sketch is -(x^2 -36) +2x, and for the other parts you need to sketch x^2 -36 +2x
Original post by Medicjug
Someone pleaseeeeeee helpppp ImageUploadedByStudent Room1433887920.628872.jpg


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I assume you've done the first part? In the second, you should end up with cos(2x-α)-cos(x)=0

What teeEm has done in the solutions is use the periodicity of cos, however, you can also write this in an alternate form using factor formula (in the formula book)
(edited 8 years ago)
Original post by Cowy97
the first part r= sqrt(1^2+sqrt3^2)
and a tan^-1 (sqrt3/1)
i think
and i would be ****ed if b came up in the exam


if only.. many would ...
Original post by Medicjug
Someone pleaseeeeeee helpppp ImageUploadedByStudent Room1433887920.628872.jpg


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Not for the faint hearted ...
Original post by TeeEm
if only.. many would ...


Teeem are you a student or a teacher


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Original post by gcsestuff
Teeem are you a student or a teacher


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neither ...
Can someone confirm that integration and implicit differentiation are not part of edexcel C3. Thanks.

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Original post by vuvuzela
Can someone confirm that integration and implicit differentiation are not part of edexcel C3. Thanks.

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confirmed
Original post by TeeEm
neither ...


Are you an examiner?


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Original post by gcsestuff
Are you an examiner?


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I am a mathematician
Original post by TeeEm
I am a mathematician


can you help me with domain and range please?
Original post by s234590
can you help me with domain and range please?


I will be if you have a specific question when I get back from my morning walk
(about 1 hour)
Original post by TeeEm
confirmed


Thanks so much

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Original post by Medicjug
Someone pleaseeeeeee helpppp ImageUploadedByStudent Room1433887920.628872.jpg


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Which IYGB paper is that?
Original post by Nurishment
Which IYGB paper is that?


I think it's p


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Original post by Gome44
I assume you've done the first part? In the second, you should end up with cos(2x-α)-cos(x)=0

What teeEm has done in the solutions is use the periodicity of cos, however, you can also write this in an alternate form using factor formula (in the formula book)


Thanksss everyone. How would writing it in cosP+cosQ help?


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