Has anyone seen a questions where they want us to explain that the period of an object with simple harmonic motion is independent of its amplitude?

Would using T= 2π√(m/k) be acceptable?
Or do we need to equate F=ma and F=kx and go from there?

Reply 988

laureeenk

How can they over complicate SHM? Any weird questions they could ask?

Reply 989

BrokenS0ulz

Does anyone have the mark scheme uses of geostationary satellites? Is it telecommunications? I feel like that's wrong

Reply 990

username1060297

For those who get confused by SHM directions!

In SHM; when velocity is positive it's moving away from the midpoint this velocity +/- is decided by directionality of displacement (away is -a hence +x, so +v).

EDIT: This is how one figures out the exchange of energy from potential to kinetic.

(edited 8 years ago)

Reply 991

Exaltation

Original post by MathsAddict

Here is the question hardest it can get tbh

And the answers? :tongue:

Posted from TSR Mobile

Reply 992

chem@uni

Original post by BrokenS0ulz

Does anyone have the mark scheme uses of geostationary satellites? Is it telecommunications? I feel like that's wrong

That and they accept Spy and weather as well

Reply 993

chem@uni

what is everyones weakest unit?

Reply 994

The Room Student

What conclusions about the motion of air molecules can be made directly from the smoke particle motion experiment?

I know that "they are moving" and "they move randomly" are acceptable, but if it was a 2 or 3 mark question, then I'd be unsure... are: "they have a range of velocities" and "they are much smaller than the smoke particles" conclusions that can be made directly?

Reply 995

Ayjayroo

Could anyone please enlighten me on this? Thanks!

Reply 996

MathsAddict

Original post by Exaltation

And the answers? :tongue:

Posted from TSR Mobile

answer for
A) 2.15ms-1
B) 4.6NS
C) 4.6m

Reply 997

chem@uni

Original post by Ayjayroo

Could anyone please enlighten me on this? Thanks!

you combine all the formulas of a cirlce show me your workings

Reply 998

Raizel

Original post by RTGSD

Can someone explain 2bii of Jan 2013 please?

I looked at the markscheme but still do't understand.

I remember this disgusting question.
Ok so basically, you know that it takes a picture of 3000km width.
You know the earth is spinning and its orbiting around the poles, so lets say it takes a picture of 3000km per orbit, you find the total distance to be covered = the circumference of earth = (2 x pi x r) (remember r being the radius of the earth not of the orbit, because it says its taking a picture of 3000km of the earth) so yeah distance needed to cover = 2 x pi x r and the distance covered by orbit is 3000km
divide total distance by distance covered per orbit to work out the number of orbits, which you get 13.4 and 14 is needed to cover it all, so it cant do it in 24 hours.
But I don't get the each orbit crosses the equator twice part because to me that means that it should take half the time but yeah I just explained what I understood.

anyone else want to help out?