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AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

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If I were to give a guide on 6 markers without even knowing the topic, I'd say:
1) Bring up relevant keys points, that you know relate directly to the topic.
2) You can never write too much, write till you know nothing else - the examiner can always extract marks from your text.
3) Look at the question and try to imagine the mark scheme, what are they looking for?

Using this helped me loads for unit 1 and 2 6 markers
Original post by CD223
Some have got me feeling like David Moyes' time as Utd manager.


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Some got me feeling like Wenger against Mourinho
Original post by HenryHein
Yes, that's right. It always helps to draw a little diagram though.

+ve E1 -------------------> charge E2 -----------------> -ve

+ve E1 ---------------------> charge E2 <--------------------- + ve


ahh yes thankyou!
whats the prediction for the 6 marker? :smile:
Reply 3625
Just wanna say thanks to everyone for making this such a lively and buzzing thread since the beginning. It's definitely helped me prepare and I hope it has for everyone else!

Let's all smash this paper!


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Original post by fruity97
I'm praying they ask about a resonance one like in the specimen paper! How the phase different varies with the driving frequency!
Anyone think it could be on transformers, energy losses? That hasn't come up in a while, would be a great 6 marker!


please can you link me the specimen paper?
Original post by CD223
Just wanna say thanks to everyone for making this such a lively and buzzing thread since the beginning. It's definitely helped me prepare and I hope it has for everyone else!

Let's all smash this paper!


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Goodluck mate, thanks for your help :biggrin:
Original post by CD223
Just wanna say thanks to everyone for making this such a lively and buzzing thread since the beginning. It's definitely helped me prepare and I hope it has for everyone else!

Let's all smash this paper!


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Agreed! *crowd roars*
Original post by a.a.k
Emf=Blv
Emf=emf zero*sin( 2*pi*f*t)

These are not in the data sheet.

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The second is implied because Emf0 is BANw and w = 2pif

The first can be derived from the data sheet:
emf= N* BA/t

Rectangular object passing through a field:
Area/ time = length* width/time
width/ time = speed
so N BA/t = N BL(w/t) = NBlv


Is it 3.6? B? ill explain if im right
Can someone please explain this question - the answer is T/2 but I thought the acceleration was in the same direction at this time?
Just my predictions here, nothing confirmed


I think the paper will be on momentum, circles, electric fields, capacitance and transformers (6 marks)
Will there be an unofficial mark scheme here tomorrow? And what about MC?
Reply 3634
Original post by HenryHein
The second is implied because Emf0 is BANw and w = 2pif

The first can be derived from the data sheet:
emf= N* BA/t

Rectangular object passing through a field:
Area/ time = length* width/time
width/ time = speed
so N BA/t = N BL(w/t) = NBlv


I wasnt expecting an explanation i just wanted to share.
Thnx anyways.


Anyother formual not in data sheet plz share


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Original post by Dante991
Is it 3.6? B? ill explain if im right


Oh sorry no I meant 6, C
Original post by Dante991
Is it 3.6? B? ill explain if im right


yes it is!!
Original post by huniibehi
This is the hardest momentum question I've seen, any ideas??

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I got the answer to be A, do you know what the right answer is?
Any 6 marker predictions? Im thinking Transformers
Original post by aprocrastinator
Can someone please explain this question - the answer is T/2 but I thought the acceleration was in the same direction at this time?


for SHM (the left one), acceleration always acts towards equilibrium and for circular motion, acceleration acts towards the centre (centripetal acceleration). At the initial time therefore, acceleration for the mass-spring system is downwards and the particle in circular motion is upwards because there's where the centre is. After half an oscillation, the particle in circular motion will be at the top and the mass on the spring will be at the bottom so opposite accelerations. Hope this helps

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