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AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

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Reply 3820
Can anyone please explain how a transformer works please?
Original post by MsFahima
oops. I understand what I've done wrong!


Oh sorry... :P it looked similar to another question asked earlier.... :biggrin:

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Original post by donutellme
Oh sorry... :P it looked similar to another question asked earlier.... :biggrin:

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No no. I edited it. My mistake. :h:

Btw, that question.. what would the potential be? 50v?
Original post by MsFahima
Potential is constant in a uniform field.


Why is it 25?
Reply 3824
Original post by EloiseFH
How are the graphs related for induced emf and flux linkage?


90 degree out if phase i think
Original post by 000alex
Why is it 25?


I'm not sure.. :/

@donutellme help please?
could someone help me on the q17 and q12 on the jan 2013 paper
Original post by 000alex
Why is it 25?


Sorry, I thought it was a different question.

Field strength is the gradient of the potential. So in a uniform field, in this case 50, the potential goes from 50 to 0. That means half way along it's gonna be 25.

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right hand rule is for what again?
Original post by Dante991
Very good question. If it says something like 'radius is doubled' etc, then formulate an equation and sub in 2r or 2m etc, and then you will find the overall equation is being multiplied by a single constant. so if F= 2m / (2r)sq, then F is being multiplied by x 2/2sq = 2/4 / 1/2 so the new force will be 1/2F. Hope this helps but these questions are the toughest


Yeah, for me it turns into an algebra treasure hunt. To luckily find the right formulas or see some way to re-arrange something into some form of an answer the question wants.

Sometimes you can miss parts out in understanding though in some algebra questions. Like once I forgot to include some part in my substitution, so a picked the one which closely resembled mine and it was right.
Original post by donutellme
Sorry, I thought it was a different question.

Field strength is the gradient of the potential. So in a uniform field, in this case 50, the potential goes from 50 to 0. That means half way along it's gonna be 25.

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So it's always in that type of ratio?
Reply 3831
Original post by Ilovemaths96
right hand rule is for what again?


Moving wire

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Reply 3832
Original post by Ilovemaths96
right hand rule is for what again?


stick your boy the thumb out and wrap them fingers around and your thumb points in current direction with fingers showing which way the magnetic field will rock up
How do I solve these?



(edited 8 years ago)
JUNE 13 Unit4.png
Can anyone help with this question? Im sure its quite simple and i might be missing something but when i use F=mw^2r, im getting 19N..

The answer is apparently D, 24N.

(this is from june 13)
how transformers work:
When alternating pd is applied to primary coil, alternating magnetic field is produced in core.
Field passes through secondary
From faraday's law and alternating magnetic flux induces emf in secondary coil

Anything to add/edit?
Original post by darkni35
JUNE 13 Unit4.png
Can anyone help with this question? Im sure its quite simple and i might be missing something but when i use F=mw^2r, im getting 19N..

The answer is apparently D, 24N.

(this is from june 13)


It's basically. Total force = Tension - mg.

So

T - mg = mw^2r

Now try. :smile:

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Reply 3838
Original post by Ilovemaths96
right hand rule is for what again?


For induced current/emf
Good Luck and Good Night guys!

Hope you all do well.

:h:

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