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Original post by Elliemay97
How do you differentiate sec^2?


I can think of two ways, use quotient rule with 1/cos^2 (taking bottom as v and top as u), or product rule using sec*sec or maybe even (sec)^2 and then differentiating normally so that's a third way. Sorry if I'm wrong though, please let me know.
Original post by Medicjug
I heard you could drop 16 marks and get full ums


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:O didnt find it that bad
what happens when you differentiate a integer value?


what -3/4 ?
Original post by Gilo98
:O didnt find it that bad


It is either 63 or 64 I can't remember which. Give me 5 minutes I'll find a table with all the pre 2014 boundaries.

Edit: it was 64/75. All the boundaries before 2014 all the way back to 2003 or whenever it started are in this thread a bit of a way down the first page http://www.thestudentroom.co.uk/showthread.php?t=2692188
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(edited 8 years ago)
Original post by BioAgent
what happens when you differentiate a integer value?


You get zero. C1 knowledge


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Original post by Medicjug
You get zero. C1 knowledge


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Ouch.
Original post by BioAgent
Ouch.


sorry didn't mean to sound mean just came across that way :smile:


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Original post by Reventón
I can think of two ways, use quotient rule with 1/cos^2 (taking bottom as v and top as u), or product rule using sec*sec or maybe even (sec)^2 and then differentiating normally so that's a third way. Sorry if I'm wrong though, please let me know.


f(x) = sec^2(x) = (sec x)^2

so f'(x) = 2 (secx) (secxtanx) = 2 sec^2(x) tan(x)
Reply 1169
Is there a technique to/formula for example sin2A= 2sinAcosA, how would you know or work out what sin3A or sin4A would expand into/look like? This also applies to cos2A and tan2A not just sine.
Original post by Nirm
Is there a technique to/formula for example sin2A= 2sinAcosA, how would you know or work out what sin3A or sin4A would expand into/look like? This also applies to cos2A and tan2A not just sine.


I dont know, but maybe you just gotta use addition formula

So sin3a = sin(2a+a)

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Is there any possible way to use the CAST diagrams to solve Sinx=0, Cosx=0 and Tanx=0 for solutions instead of the graph's?
how do you get range of functions that look like this:

1/(x+1)(x-1) or 2x/(3x+5)

like also how do i know when to say y is not equal to 0 as part of the range answer

help?
Original post by Nirm
Is there a technique to/formula for example sin2A= 2sinAcosA, how would you know or work out what sin3A or sin4A would expand into/look like? This also applies to cos2A and tan2A not just sine.


As It's a me mario says, use sin(2a+a), or if you're feeling really exotic you can use de moivres theorem (fp2)
Original post by Maham88
what -3/4 ?


I substituted it into the original equation and did the positive mod and negative mod and solved
Original post by adorablegirl1202


This video explains exactly how to do it https://www.youtube.com/watch?v=SOb5ncF6x2I
Original post by Hash1mate
Is there any possible way to use the CAST diagrams to solve Sinx=0, Cosx=0 and Tanx=0 for solutions instead of the graph's?


Yes it's the exact same as doing it for any other question?
I'm kinda upset, really want an A* but I always make dumb mistakes that lose 5-10marks
Original post by anonwinner
I'm kinda upset, really want an A* but I always make dumb mistakes that lose 5-10marks


Just do the exam really slowly and check your answer after very question and then check everything again at the end. Just do that in a few past papers today and see if you come out any better?

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