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AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread]

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Any one else get A A A as the first three MC?


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Original post by king cobra
What about the angle in degrees ?


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131 ish?
my answers i can remember
forced vibration made by driving force and are in phase, amplitude smaller than at resonance
resonance is at natural frequency and 90 out of phase amplitude large
ring did affect the pendulum THIS IS WRONG THOUGH :-(
RING DOESNT AFFECT DAMPING I DONT THINK
coulombs law: force of two point charges is inversely proportional to the square of distance and proptional to the product of its charges
3300 electric field strength
no. of rotations 0.3 ?
degress angle 2.2
tension 12.34
graph half the current at start then levels out to the same point as other curve
6 mark
Quote three laws, mention centripetal force and acceleration, velocity changes
Not horizontal due to gravitaion force
unit wb (flux linkage) 0.0608 ? not sure
4.48v somthing for emf
I put that damping was greater with ring because restoring force was proportial to mg, and energy was Fs so energy was mgs which is dependent on mass, high mass means higher energy lost to resistive forces. No idea if its correct, I was babbling
Original post by annierox1863
my answers i can remember
forced vibration made by driving force and are in phase, amplitude smaller than at resonance
resonance is at natural frequency and 90 out of phase amplitude large
ring did affect the pendulum THIS IS WRONG THOUGH :-(
RING DOESNT AFFECT DAMPING I DONT THINK
coulombs law: force of two point charges is inversely proportional to the square of distance and proptional to the product of its charges
3300 electric field strength
no. of rotations 0.3 ?
degress angle 2.2
tension 12.34
graph half the current at start then levels out to the same point as other curve
6 mark
Quote three laws, mention centripetal force and acceleration, velocity changes
Not horizontal due to gravitaion force
unit wb (flux linkage) 0.0608 ? not sure
4.48v somthing for emf


You have the angle in radians there, it asked for degrees
Original post by king cobra
What did u get ?


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Let me go to a coffee shop so that i can take a picture


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Anyone else notice on the current graph question that the first resistance was 150Ω, but the second was 300KΩ? Think it was probably a typo on AQA's behalf, because the resulting graph would have to start with initial current 2000x lower than the original graph.
Original post by Cmog
For the ring/cone pendulum did anyone put that it has no impact upon the damping?
Because damping is the work done by external forces isn't it? and there is no mention of mass in the velocity/acceleration/displacement/time period equations for a pendulum??


I put no impact, not sure if its right!
That capacitor question annoyed me so much. I was internally raging. I worked out that the current dips 1/400 of a square.

It still annoys me now. Here's a graph of a capacitor discharging, what happens when we times the resistance by 2000?

Now try and draw that on the same axis.
B******s
First 5 MC I got CAADA but i'm sure the first is wrong


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number of rotations i got 2????
Original post by Fred Cantoni
Any one else get A A A as the first three MC?


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No, D A A
D was the correct answer as Rate of change of momentum is F = (mv-mu)/t
force unit is Newtons
Original post by Klaxoii
First 5 MC I got CAADA but i'm sure the first is wrong


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Think I got AAADD :/


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This http://youtu.be/HV4FNXt1F6Y shows that without ring has heavier damping


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Bit of an odd paper-personally found MC easier than the written paper...
Waiting for UNNOFICIAL markscheme .... Hopefully should have one by this evening?
Reply 3955
Original post by cudders96
Anyone else notice on the current graph question that the first resistance was 150Ω, but the second was 300KΩ? Think it was probably a typo on AQA's behalf, because the resulting graph would have to start with initial current 2000x lower than the original graph.


Was it steeper gradient with less area under graph, I forgot to adjust my current :angry:
Reply 3956
Original post by Ilovemaths96
number of rotations i got 2????


Same, is that for circular motion part?
Original post by Ilovemaths96
number of rotations i got 2????



I got that too! Thought it was wrong cuz everyone says different things lol
Original post by davidharris96
No, D A A
D was the correct answer as Rate of change of momentum is F = (mv-mu)/t
force unit is Newtons


Oh I think I put newtons... Maybe I didn't put A...


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Original post by Cmog
Was it steeper gradient with less area under graph, I forgot to adjust my current :angry:


It was a typo. You physically couldn't draw the graph as the current was so small.

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