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OCR MEI C3 Maths June 2015

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Wait how did people get 4-ln(3) for the area underneath?

The line intersected at 1 and 4

Area of rectangle = 3 x 1 ?
Reply 341
How did you do the arccosx = arcsinx? I got x=1/4 pie...
Original post by Lord-Febreeze
what was the formula of they function that we had to differentiate twice in q8? im sure it wasnt (x-2)2/2 as has been said earlier, although i could be wrong


Replace the 2 with an x
Did everyone remember to add "+ c" at the end of answer in question 2??
What did everyone get for the y value for the first question?


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Original post by chizz1889
Will I lose a mark for saying 'x= (root2)/2' I didn't put +/- but it was only a two mark question


-root2/2 doesn't work as a solution


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Original post by QueNNch
Did everyone remember to add "+ c" at the end of answer in question 2??


Yeah although in mark schemes at c3 they usually condone omission of c
Original post by QueNNch
Did everyone remember to add "+ c" at the end of answer in question 2??


Ahh ****


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Original post by Gcseboy1997
-root2/2 doesn't work as a solution


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Oh yeah 😂😅 got 2/2 there then ☺️
Original post by QueNNch
Did everyone remember to add "+ c" at the end of answer in question 2??


Wasn't it +0.5c because you multiply by a half? Help!!
Original post by ThatWasHard!
Wasn't it +0.5c because you multiply by a half? Help!!


No if you multiply c by any constant then it remains as c as c represents a constanct you don't know ☺️
Original post by Jim997
How did you do the arccosx = arcsinx? I got x=1/4 pie...


arccosx= -arcsinx +1/2pi
Therefore 2arcsinx -1/2pi = 0
Therefore arcsin x= 1/4 pi
Therefore x =sin(1/4pi)
Therefore x= root2/2 :-)


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Original post by chizz1889
No if you multiply c by any constant then it remains as c as c represents a constanct you don't know ☺️


Would a mark be taken off for that?
Vote on the difficulty of this paper here:http://strawpoll.me/4609673
Original post by Gcseboy1997
arccosx= -arcsinx +1/2pi
Therefore 2arcsinx -1/2pi = 0
Therefore arcsin x= 1/4 pi
Therefore x =sin(1/4pi)
Therefore x= root2/2 :-)


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Or you can do arccosx=theta=arcsinX
X=costheta=sintheta
Tantheta = 1 so theta = pi/4 x=sin(pi/4)=root2/2
Reply 355
Original post by Gcseboy1997
arccosx= -arcsinx +1/2pi
Therefore 2arcsinx -1/2pi = 0
Therefore arcsin x= 1/4 pi
Therefore x =sin(1/4pi)
Therefore x= root2/2 :-)



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Wow we've never been taught that ...
Original post by chizz1889
No if you multiply c by any constant then it remains as c as c represents a constanct you don't know ☺️

What did you get for the question where you had to calculate the area between y=1 and the curve?

Wasn't it 3 x 1? Since it intersects at 4 and 1

So 3 - Integral of the Curve
Reply 357
i did **** in this paper. reckon i got max 50 marks. If i got 16/18 in the coursework then will that pull up the C3 grade much from the C average it says i'll get from looking at the past papers?
Reply 358
Would I loose marks on 6 (I) for leaving the answer as x= sin(pie/6) ?
What a beautiful exam.

I ran out of time on the last question but should get marks for working out and the graph. (didnt label the intersects though but yolo)

That and arccosx = arcsinx which I had no clue about which was only 2 marks. I lost around 6 marks in that exam. Could only afford to lose 4 for the 90% A* so need to bang out on dreaded c4.

Every question in that paper was from a past paper! Loved the rates of change one!
It was literally copying and pasting from papers I've done but changing the numbers around :smile:

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