Look where it says integral of cosec, you use the log laws to raise the powers and deduce that cosec plus cot is 1/ tan(1/2x)

Can you look at my post above for help please?

Reply 707

Rkai01

How is first q done. The induction one? I tried writing it in a form of differentials but went awkward.

Preferably a written solutions with pictures please

@Zacken

(edited 7 years ago)

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Reply 708

economicss

Original post by Rkai01

Look where it says integral of cosec, you use the log laws to raise the powers and deduce that cosec plus cot is 1/ tan(1/2x)

Can you look at my post above for help please?

Thank you

damn that question on my list of ones I can't do aswell, will give it another go now :smile:

Reply 709

Rkai01

Original post by economicss

Thank you

damn that question on my list of ones I can't do aswell, will give it another go now :smile:

And the induction q if u can

Reply 710

economicss

Original post by Rkai01

And the induction q if u can

I've found the radius, but stuck on how to find the y-coord of the centre!

Reply 711

Rkai01

Original post by economicss

I've found the radius, but stuck on how to find the y-coord of the centre!

That's exactly where I am dude.

Reply 712

economicss

Original post by Rkai01

That's exactly where I am dude.

It's probs a circle theorem of some kind but can't think what, will ask my teacher on monday and post his working :smile:

Reply 713

Rkai01

Struggling with this.
First 2 pics shows approach 1 and 3rd is second approach

With 4th pic showing q which is 9b
@oinkk

(edited 7 years ago)

Original post by Rkai01

How is first q done. The induction one? I tried writing it in a form of differentials but went awkward.

Preferably a written solutions with pictures please

@Zacken

Assume true for n=k and then differentiate once more and algebra manipulate to show that it's true for n=k+1. If you're stuck then post your solution.

Reply 715

Rkai01

Original post by economicss

It's probs a circle theorem of some kind but can't think what, will ask my teacher on monday and post his working :smile:

Wait what did you get for radius? How'd you get it

Reply 716

economicss

Original post by Rkai01

Wait what did you get for radius? How'd you get it

2root3, used 2 of the points I already knew with the C2 distance formula on (7,4) and (4, 4+root3) then did (x-x1) squared + (y-y1 squared) with those two coords :smile:

Reply 717

Rkai01

Original post by economicss

2root3, used 2 of the points I already knew with the C2 distance formula on (7,4) and (4, 4+root3) then did (x-x1) squared + (y-y1 squared) with those two coords :smile:

Ya I got 2root 3 but for distance between 7,4 and 4,4+root3 but why is that length the same?
This is the logic I put together as to why the centre is what it is but I don't get why distance are the same and hence both are root3 downwards from 4,4 +root3

EDIT: I don't know why but the bottom triangle might be the same as top
which is why they got what they got but could be wrong.

SEE 2 posts below for second pic.

Confirmation @Zacken

(edited 7 years ago)

image.jpg437.9KB

Reply 718

oinkk

Original post by Rkai01

Struggling with this.
First 2 pics shows approach 1 and 3rd is second approach

With 4th pic showing q which is 9b
@oinkk

I have not attempted this question yet, but here are my initial thoughts. If this doesn't help then I'll take a look at it tomorrow morning.

Your second attempt is the right approach.

You need your argument to just be in one plane, the w-plane. Make z the subject of the transformation, and add 2i to both sides of the transformation to achieve the expression you desire :smile:

Reply 719

Rkai01

From above post

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