Edexcel FP2 Official 2016 Exam Thread - 8th June 2016

You get dy/du but the squared I got was of (du/dx). You know du/dx is 1/x so this is 1/x^2 (which you then substitute in).

Guys what did you get for the area of the polar curves? I got 71.0 or 49pi/2 + (3root7)/4 -11arccos3/4

Guys what did you get for the area of the polar curves? I got 71.0 or 49pi/2 + (3root7)/4 -11arccos3/4

:O ... I didnt rearrange x=e^2u (is that what it was or was it e^u?) as ln|x|=2u
Instead I attempted to straight away differentiate x with respect to y and then flip it which I think led me very off track, cheers for the reply

So I've confused myself on redoing part b of the polar co-ordinates question.

I did this, and I'm struggling to see why I only got 15 rather than 35. Surely this gives the required area?

$2.\frac{1}{2}\int_{0.722}^{\frac{\pi}{2}}(7cos\theta )^2 + \frac{(2 * 0.722)}{2\pi}*(r)^2$

First part evaluates to 8.64 and the second part evaluates to 6.33, giving a total of ~15?

Will release one tomorrow.

Ok basically i was in a hurry and wrote arccos as arcos (spelling mistake) would i lose marks?

hi ,
tbh it was too iz for me,
i fought they wld make it a bit challenging coz its the third fp module.
well see ya later nerds get good scrubs
looking forward to fp3 for another 100ums
lots of love,
ms wier

Did anyone else still have an e^u they were unable to get rid of in their equation after they'd substituted in Q7a? If the x^2 in front of the first term of equation 1 was instead an x I'd have got the answer.


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How many marks do you guys think I've lost if I didn't integrate e^2θ sinθ and left it in term of the integral?

To be honest, apart from Q4, they were all standard questions. There were two obvious ways to approach 4b, one was treating it as a 1st order differential and finding the integrating factor etc. and the second method was differentiating it again and treating it as a 2nd order then solve. A*-70?