UNOFFICIAL MARKSCHEME Edexcel Maths Calculator paper 09/06/2016

Let me know if you find out about mr kirbia please!!! ☺️

um hang on, arent u meant to test 3.75 and 3.75 is less than 34, therefore x has to be in between 3.75 - 3.8

X³-5x=34.
Assuming X=3.7 would give an answer of 32.153, its difference from 34 being 1.847. However, assuming X=3.8 would yield an answer of 35.872, its difference from 34 being 1.872. Since the difference between 34 and the value of X as being 3.7 is smaller than the value at 3.8, X=3.7.
Hope this helps.

3 marks for stem and leaf diagram 1 mark for 9/20

Wat is it roughly to get a C grade??

There was a big debate earlier, i put 3.7 but either way, a few marks cant make a massive difference

Anyone know how many marks I will get for putting 9/20 for the 2nd question instead of 0.45?

Hi I'm going to start and unofficial markscheme so add your answers
Reps are not necessary but would be appreciated

Sorry for the hold up with the questions
1. Order numbers correctly and include a key (Stem and leaf) (3 marks)
b) 9/20=
0.45 (2 marks)
2a. 5a*2b*3c =
30abc (1 mark)
b. Factorise fully 3y +6 =
3(y+2) (1 mark)
c. Expand x(x-3)=
x^2-3x (1 mark)
3. Perimeter of a rectangle with side lengths x and x+4 is 45
x+x+x+4+x+4= 4x+8
4x+8=45
4x=37
x=9.25 (3 marks)
4. Smallest packet was best value for money because it was cheapest per bag of crisps (4 marks)
5. 4 times as many red than green: There were 0.4 blue and 0.15 yellow.
0.4+0.15+4x+x=1
0.55+5x=1
5x=0.45
x=0.09
4x=0.36
Green- 0.09 Red- 0.36 (3 marks)
6a. Body mass index= m/h^2
Mass= 50kg
Height= 1.57m
20.3 (2 marks)
b. What mass will result in a BMI of 21 with a height of 1.8m
68.04kg (2 marks)
c. Tom's skis can be a maximum of 145% of his height what is their max. tenght (Tom is 1.8m)
2.61m (3 marks)
7. Trial and error. x^3-5x=34 with a number between 3 and 4
3.8 (4 marks)
8a. Photographs with of width 720 pixels and a height of 540 pixels what is the ratio width:height in its simplest form?
4:3 (2 marks)
b. The person now wants the ratio to be 2:3, without changing the width of the picture, what is the new height?
480 pixels (2 marks)
9.x= 124 degrees (4 marks)
10. Mean of grouper freq. table 396(freq.*midpoint total)/50 (freq. total)
7.92 (4 marks)
11. Colin's drive to work
£42.29 (5 marks)
12. The middle angle of a pentagon
x=144 degrees (4 marks)
13.
-2 -1 0 1 2
-1 3 1 -1 3 (2 marks)
Draw curve (2 marks)
14. steel bar with length of 120cm and a cross sectional area of 72cm^2 and a density of 8g/cm^3. A trolley can carry 250kg so how many bars can it carry?
3 Bars (5 marks)
15. Pauls buys a car worth 15,000 pounds and the value depreciates by 23% in the first year and 18% after the first year. Has Paul's car lost half of its value in theree years?
No, because 7766.22 was greater than 7500 pounds (4 marks)
16. Median on cumulative freq. graph
128g (1 mark)
b. Use graph to find interquartile range
11g (2 marks)
17. Triangle with sides 15.6cm (opp), 18(hyp). Angle is split into 2, 30 degrees and x degrees. the whole angle is 60.1 so
x=30.1 (4 marks)
18. 10a^5b^4 (2 marks)
b. y= 5p^2-x (3 marks)
19. 51 out of the 234 were maths in yr 12 so 50 * 51/234
11 males (2 marks)
20. 3x^2 + 6x -2
x= 0.29 or x= -2.29 (3 marks)
21. v=14 to 2 s.f u= 8.7 to 2 s.f
What is the upper bound of I when I= 5(v-u)
29.25 (3 marks)
22. Histogram -F.d- 1.6, 3.2, 2.4, 1.8, 0.3 (3 marks)
23. Perimeter of the shaded part of the sector.
Measurements were 4+4+5/2pi+25/6pi
28.9 (3 marks)
24a. Simplify (3-x)/3x^2-5x-12
-1/3x+4 (2 marks)
b. Write are one fraction in its simplest for (x/x-1)- (x/x+1)
2x/(x+1)(x-1) (3 marks)
25. Triangle with side lengths 7 and 8 finding the top angle using 1/2absinC , sine rule and cosine rule
80.4 (6 marks)

It's an anomaly, a big one.

However, your'e looking at an equation with the highest power being 3, the change in increase gains as you input a greater number so the fact that you said 3.8 has a larger difference still doesnt prove that it is further away from the true value.
On the other hand, it is a fact that as the value of x increases in the equation, the numerical value also increases so the only way we can find whether x is closer to 3.7 or 3.8 is by using the midpoint 3.75, if the value is smaller than 45 when inputting 3.75 then we know that x is larger than 3.75, hence any number above 3.75 would be closer to 3.8 than 3.7

Yeah, I know, but the papers this year seem roughly the same difficulty.

Answers to every question

I think I only dropped 4-5 marks. YEY ME.

if you did it how u said u did it and showed that, you should get marks tbh

No, it was a lot easier.