AQA A2 Mathematics MPC3 Core 3 - Wednesday 15th June 2016 [Official Thread]

Original post by fpmaniac

Find the values for x for which
$|x-3|<5-|x|$

I need to check this but I got x = -1, x = 4 so:

- 1 < x < 4

(edited 7 years ago)

Reply 321

fpmaniac

Yep, thats right :smile:

Original post by Suits101

I need to check this but I got x = -1, x = 4 so:

- 1 < x < 4

Reply 322

Original post by fpmaniac

Yep, thats right :smile:

Yup just checked my working and I'm happy with it and then checked it on graphical calc (life saver)!

:smile:

Reply 323

SunDun111

Guys they is something dodgy with my graphical calcutor casio I type in Sin (inverse) (3X) so its been stretched by 1/3 but for some reason the Y end points changes for some reason any ideas why?

Reply 324

MahuduElec

5

Original post by Yo12345

Just use substitution. 3x^2du = dx. So you get : 3(x^3-10)^7/7 + C

Posted from TSR Mobile

it was meant to be done without a substitution, as it's in the form f'(x)(f(x))^n

For C3 they hardly ever ask this type of question, I've seen it come up once for 2 marks. But for units like FP3 etc, this trick is more useful as it's quicker if you know how it works.

Reply 325

Original post by SunDun111

Guys they is something dodgy with my graphical calcutor casio I type in Sin (inverse) (3X) so its been stretched by 1/3 but for some reason the Y end points changes for some reason any ideas why?

That's strange... And what's even stranger I didn't know you could plot inverse trig function on a calculator!

Reply 326

Z.e.e

7

Original post by AlexM10

Any ideas for 5B june 2014??

Complete the square on the quadratic and you'll find it'll make things a lot easier

Reply 327

whydoidothis?

21

Original post by Suits101

These have never come up before, but I have written a solution to it:

Page 160
Exercise 9B
Question 7

I have never seen questions like these before!

Could I see your solution? I can't seem to get the answer.

Reply 328

Original post by MahuduElec

Integrate x^2(x^3-10)^6 .dx

I made this up, but using that 'reverse chain rule', you can do this in two or so steps without parts/substitution.

Could you/anyone write this in LaTex?

Reply 329

whydoidothis?

21

Original post by SunDun111

Guys they is something dodgy with my graphical calcutor casio I type in Sin (inverse) (3X) so its been stretched by 1/3 but for some reason the Y end points changes for some reason any ideas why?

My calc messes up inverse graphs too.
You need to draw the graph of inverse sign then just apply the transformations to your endpoints in the exam.

Th calc draws normal inverse graphs fine (without transformations) so its ok.
I think there is a way to fix it though, don't know much about my calculator =(.

Reply 330

whydoidothis?

21

Original post by Suits101

Could you/anyone write this in LaTex?

The question or the solution using reverse chain rule?

Also could you post the solution to that question please. the quotething messed up.

Reply 331

MahuduElec

5

Original post by Suits101

Could you/anyone write this in LaTex?

Sorry, I've never used/ know how to use LaTex

Reply 332

SunDun111

How is everyone feeling then? I am getting 60's on some papers and high 50's on others, Not sure what to expect, Ngl i usually get 10 marks lower in the exam.

Reply 333

Original post by whydoidothis?

.

The bit after below:

= 2sin^-1(2x) + C

Therefore overall integral = -0.25(1-4x^2)^0.5 - 2sin^-1(2x)

Then just put limits in :smile:

(I didn't see limits originally hence all the + C stuff)

Spoiler

(edited 7 years ago)

Reply 334

SunDun111

hey guys if i was asked to sketch a random inverse graph how would I do it

Reply 335

FluorescentM

3

Can anyone help I'm not sure how to go about finding the area on Q8d
Question paper -
http://theallpapers.com/papers/AQA/ALevels/Mathematics%20(6360)/AQA-MPC3-W-QP-JUN05.pdf
Mark scheme -
http://theallpapers.com/papers/AQA/ALevels/Mathematics%20(6360)/AQA-MPC3-W-MS-JUN05.pdf

Reply 336

aoxa

Original post by FluorescentM

Can anyone help I'm not sure how to go about finding the area on Q8d
Question paper -
http://theallpapers.com/papers/AQA/ALevels/Mathematics%20(6360)/AQA-MPC3-W-QP-JUN05.pdf
Mark scheme -
http://theallpapers.com/papers/AQA/ALevels/Mathematics%20(6360)/AQA-MPC3-W-MS-JUN05.pdf

Find the y value when x is 2 and 4. Then area B = Rectangle of where x=4*y(4) - area A - rectangle where x=2*y(2)

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Reply 337