For this question, it later asks about how propan-2-ol will react in this 2 part experiment.
So the first part shows complete oxidation and the second is the partial oxidation only.
I don't understand why secondary alcohol will can be distilled (in the second part of the experiment) to also form a ketone. I thought the conditions to turn a secondary alcohol to a ketone must be to heat under reflux and use excess dichromate? How can it also be distilled to form a ketone?
For this question, it later asks about how propan-2-ol will react in this 2 part experiment.
So the first part shows complete oxidation and the second is the partial oxidation only.
I don't understand why secondary alcohol will can be distilled (in the second part of the experiment) to also form a ketone. I thought the conditions to turn a secondary alcohol to a ketone must be to heat under reflux and use excess dichromate? How can it also be distilled to form a ketone?
Thanks
You don't need particularly harsh conditions to oxidise a secondary alcohol to a ketone. So both procedures here will do the job.
This is different from a primary alcohol like ethanol where a weak oxidising agent will turn it into an aldehyde and a strong oxidising agent will turn it into a carboxylic acid
You don't need particularly harsh conditions to oxidise a secondary alcohol to a ketone. So both procedures here will do the job.
This is different from a primary alcohol like ethanol where a weak oxidising agent will turn it into an aldehyde and a strong oxidising agent will turn it into a carboxylic acid
What about the reagent then? Does it need to be in excess for secondary alcohol to be oxidised?
If you are distilling off the ketone then it shouldn't matter, you will still get the ketone (but it wouldn't go to completion of course)
I meant if I am to heat the secondary alcohol under reflux to produce the ketone (since this also works), will an excess amount of reagent needed in this case?