f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ if\ x<2} \\ {\dfrac{2}{x^2}\ if\ x\geq 2 }\end
f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ (-\infty ,\dfrac{1}{2})} \\ {\sqrt \dfrac{2}{x} [\dfrac{1}{2}, \infty) }\end
f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ (-\infty ,\dfrac{1}{2})} \\ {\sqrt \dfrac{2}{x} [\dfrac{1}{2}, \infty) }\end
f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ \text{if}\ x<2} \\ {\dfrac{2}{x^2}\ \text{if}\ x\geq 2 }\end
f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ (-\infty ,\dfrac{1}{2}\right{)}} \\ {\sqrt{\dfrac{2}{x}} \text{ } \left[\dfrac{1}{2}, \infty) }\end
f(x)= \begin{cases}{ \frac{5}{2}-x & \text{if } x<2} \\ {\frac{2}{x^2} & \text{if } x \geq 2 }\end{cases}
f(x)= \begin{cases}{ \frac{5}{2}-x & x \in (-\infty ,\dfrac{1}{2})} \\ { \frac{2}{\sqrt{x}} & x \in [\frac{1}{2}, \infty) }\end{cases}
f(x)= \begin{cases}{ \frac{5}{2}-x & \text{if } x<2} \\ {\frac{2}{x^2} & \text{if } x \geq 2 }\end{cases}
f(x)= \begin{cases}{ \frac{5}{2}-x & x \in (-\infty ,\dfrac{1}{2})} \\ { \frac{2}{\sqrt{x}} & x \in [\frac{1}{2}, \infty) }\end{cases}
f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ \text{if}\ x<2} \\ {\dfrac{2}{x^2}\ \text{if}\ x\geq 2 }\end
f(x)= \begin{pmatrix}{ \dfrac{5}{2}-x\ (-\infty ,\dfrac{1}{2}\right{)}} \\ {\sqrt{\dfrac{2}{x}} \text{ } \left[\dfrac{1}{2}, \infty) }\end
f(x)= \begin{cases}{ \frac{5}{2}-x & \text{if } x<2} \\ {\frac{2}{x^2} & \text{if } x \geq 2 }\end{cases}
f(x)= \begin{cases}{ \frac{5}{2}-x & x \in (-\infty ,\dfrac{1}{2})} \\ { \frac{2}{\sqrt{x}} & x \in [\frac{1}{2}, \infty) }\end{cases}
[br]f^{-1}(x) = \begin{cases}[br]\frac{5}{2} - x, & \text{with range}, \, (-\infty, 2),\\[br]\sqrt{ \frac{2}{x} }, & \text{with range}, \, [2, \infty).[br]\end{cases}[br]
[br]f(x) \, = \, \begin{cases} \frac{5}{2} - x, & \text{where} \, x < 2, \, \text{has range} \, (\frac{1}{2}, \infty),\\[br]\frac{2}{x^{2}}, & \text{where} \, x \geq 2, \, \text{has range} \, (0, \frac{1}{2}]. \end{cases}[br]
[br]f(x) \, = \, \begin{cases} \frac{5}{2} - x, & \text{where} \, x < 2, \, \text{has range} \, (\frac{1}{2}, \infty),\\[br]\frac{2}{x^{2}}, & \text{where} \, x \geq 2, \, \text{has range} \, (0, \frac{1}{2}]. \end{cases}[br]
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