An unknown metal carbonate reacts with a hydrochloric acid according to the following equation:
M2CO3(aq) +2HCl(aq) -----> 2MCl(aq) + CO2(g) + H2O(l)
A3.44 g sample of M2CO3was dissolved in distilled water to make 250 cm^3 of solution. A 25.0 cm^3 portion of this required 33.2 cm^3 of 0.150 mol dm^-3 hydrochloric acid for complete reaction.
part 1) calculate the amount, in moles, of HCl in 33.2 cm^3 of 0.150 mol dm^-3 hydrochloric acid.
part 2) calculate the amount, in moles of M2CO3 that reacted with this amount of HCl.
part 3) calculate the amount, in moles, of M2CO3 in the 3.4 g sample.