Contour Integral

No replies... damn what happened to TSR... I remember when I did A-Level maths people used to reply very very quickly...

Guess all the maths geniuses have moved on from TSR

Probably would have helped if your original post wasn't missing the actual integral.

Attitude now isn't helping either...

Hello I can change the integral into a circle integral etc

but don't know how to deal with the P?

Any help thanks.



Integral d(theta) / ( 1- 2pcos(theta) + p^2 ) with limits 2pi,0

Complete the square in the denominator to get $(p-\cos \theta)^2 + \sin^2 \theta$ in the denominator

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I attached an image and also entered a tinypic link, it doesn't seem to have gone through though. The integral was written but it wasn't written very clearly. I edited it now hopefully it is more clear.

Sorry if it came across that way but that was not my intention, it was just an observation.

Obviously I'm on a site where people give help to people like myself for free, I didn't mean to come of as self entitled, sorry about that.

Because you are a new user, if you post links they will need to be approved first (to prevent spam etc.). I approved your post but I think you may have deleted the image.

As you post more your posts won't need to approved. Best to use an original account instead of starting a new one...

Complete the square in the denominator to get $(p-\cos \theta)^2 + \sin^2 \theta$ in the denominator

I assume he wants to do it by contour though.

If $z = e^{i\theta}$ then z + 1/z = 2 cos theta.