What is Jenny's new standard deviation after she gets the highest possible mean?
Q (part c): http://prntscr.com/ts5k6nMy w/o: http://prntscr.com/ts5kcbWhat did I do wrong?
Original post by TSR360
Q (part c): http://prntscr.com/ts5k6nMy w/o: http://prntscr.com/ts5kcbWhat did I do wrong?
edit - they give 14.0% as the answer. They've rounded to 1do so your working is correct.
(edited 3 years ago)
Original post by mqb2766
edit - they give 14.0% as the answer. They've rounded to 1do so your working is correct.
The answer is 12.1% in my textbook...
Original post by TSR360
The answer is 12.1% in my textbook...
The answer in the Google books version is 14.0℅.
Sounds like a typo in your edition.I got the same as you.
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