Numerical solutions of eq

I dont understand how to do question 9(a)

What do you understand?
Its a relatively simple area question with a bit of working required on the radius of the sector?

If you work back from the answer, can you spot any structure?

Is it that i have to calculate the area of triangle ABC?

You could do but you'd have to do the additional segment as well. Isn't the sector easier?
Try and write down some equations and upload when you get stuck.

Did you try working backwards?

You could do but you'd have to do the additional segment as well. Isn't the sector easier?
Try and write down some equations and upload when you get stuck.

Did you try working backwards?

So I did area of shaded region= area of circle - area of sector abc.
Area of shaded region = 3/8× area of circle

Area of sec acb = 1/2 r^2× 2 theta

isn't the shaded region the sector?
What variables, formulae, ..
Did you try working backwards...

That radius is not r

That radius is not r

isn't the shaded region the sector?
What variables, formulae, ..
Did you try working backwards...

You mean I use the expression theta=cos^-1sqroot

oh yeah right

A couple of things
* Step away from the reply button for a time and draw/think about the problem
* Work back from the answer, can you get an "area = 3/8 area" type expression. Does that give you any hints?
* Draw 0A and/or OB on your diagram. How does that help you relate the radii.

Upload your thoughts/working after a bit of thinking. There is nothing beyond a hard gcse question here. Working backwards from the desired expression can, in some cases, give you hints about how the analysis is done.

A couple of things
* Step away from the reply button for a time and draw/think about the problem
* Work back from the answer, can you get an "area = 3/8 area" type expression. Does that give you any hints?
* Draw 0A and/or OB on your diagram. How does that help you relate the radii.

Upload your thoughts/working after a bit of thinking. There is nothing beyond a hard gcse question here. Working backwards from the desired expression can, in some cases, give you hints about how the analysis is done.

Iam not understanding how to approach this question. Can you pls explain in a simpler way if possible?

Iam not understanding how to approach this question. Can you pls explain in a simpler way if possible?

What picture have you drawn? What equations are you using for the area of the circle / sector. Working backwards steps would be appreciated. Can you p!s upload what you've done.
Please give me something to work wit

So, I assume you're happy that if we knew the radius R of the sector, then the area of the shaded region would be R^2 theta?

So what you really need to do at this point is find out what R is. This is basically GCSE geometry, but it seems to be something a lot of A-level students struggle with.

You know two sides of the triangle AOC = r. So, that triangle is isoceles. Does that help?

so Ac = sqroot(2) ×r

Why (and no)?

Since oc is perpendicular to oa and ob

Where does it say that in the question?