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    (Original post by Maths degree)
    What was the answer to why they can't be an inverse function of g(x)
    Because g(x) is a many to one function and thus cannot have a inverse.
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    The question asking whether it was increasing or decreasing: I put decreasing, because it was a transformation of 1/x and k was a negative constant and x>=1
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    (Original post by BFP=big fat poo)
    I did so crap on my D1 i got 60 UMS I reckon so I needed 180UMS more to get an A*, thats not happening now
    clearing for you mate
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    (Original post by `God)
    very easy paper, expect very high grade boundaries.

    won't even be surprised if its 73 for A*/90UMS.

    I predict:

    75 -100
    73 -90
    70 -80
    who cares about the rest
    Nah fam, that's too low.
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    I found this paper much easier than the June 2014 one, anyone else agrees? I think the grade boundaries will be fairly standard? Also to prove cos theta on q1b I used a right angled triangle with hypothenuse sqrt(1+p^2) but when writing down the answer I copied the hypothenuse value wrong to get 1/sqrt(1-p^2). Would I get any method marks?
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    (Original post by jennyh1)
    Made a couple of silly mistakes but found it fine, hopefully I got the 90 ums
    highly doubt that, stop dreaming.
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    (Original post by lukass)
    for 8b) where

    sec 2y + tan 2y = 1

    how did people do this?? I was so confused...
    Sub in the 'show that' value from part a) for sec2y + tan 2y then it's pretty simple from there
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    for temperature question, I got lambda = ln(0.5)/-40 ?
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    (Original post by lollipopsftw)
    patiently waiting for Arsey
    Im a noob here. Who is this arsey?
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    Attachment 426223426225Attachment 426223426225426240Name:  010.jpg
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    (Original post by anndz3007)
    Here is my answer, in random order th
    2p/1-p^2,1/(1-p square)^1/2, (p+1)/1-p
    Ln7/2,ln3/2
    51.8,-25.3
    K>33/8
    Coordinate=( 0,pi/3)
    93 sec
    3.1,13.9
    -4e^-4<y<1/e something
    Fx Decreasing
    I got k<-2root5 and k>2root5 as it is above and below the max and min point
    yh it was -4e^-4<=g(x)<=1/8e
    fx is increasing
    other than that seems right
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    You're not a member of The Student Room if you don't know Arsey.
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    My teacher said that it was quite easy for C3 (compared to last year and the year before) so expect high grade boundaries!
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    (Original post by Kabulkid)
    IT WAS EASY BUT NOT THAT EASY, i predict

    75 - 100
    72 - 90
    68 - 80
    lol if u get below an A get off TSR
    75 - 100
    74 - 0
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    (Original post by Nightmare8)
    That's because you need 270/300 from c3 c4 and fp2 for an A*. That's for further, I don't know about the rest
    He's not doing further pure math. He's doing further math which is different.
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    (Original post by `God)
    very easy paper, expect very high grade boundaries.

    won't even be surprised if its 73 for A*/90UMS.

    I predict:

    75 -100
    73 -90
    70 -80
    who cares about the rest
    Mate I totally agree with you, like that paper was p*** easy I could have done that while asleep. Actually I could have done it while doing C4 too, that's how easy it was.....STFU^^ and GTFO
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    (Original post by Hectors)
    I found this paper much easier than the June 2014 one, anyone else agrees? I think the grade boundaries will be fairly standard? Also to prove cos theta on q1b I used a right angled triangle with hypothenuse sqrt(1+p^2) but when writing down the answer I copied the hypothenuse value wrong to get 1/sqrt(1-p^2). Would I get any method marks?
    It said to use trig identities so I'm not sure if that would get marks. I suppose SOHCAHTOA is an identity though...
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    (Original post by Chazley123)
    for temperature question, I got lambda = ln(0.5)/-40 ?
    not -
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    (Original post by Kabulkid)
    another one makes a rookie error, tut tut.
    please go on?
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    If they didn't specify to give an exact value-would you still lose marks for giving decimals
 
 
 
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