The Student Room Group

Scroll to see replies

Original post by Maths degree
What was the answer to why they can't be an inverse function of g(x)


Because g(x) is a many to one function and thus cannot have a inverse.
The question asking whether it was increasing or decreasing: I put decreasing, because it was a transformation of 1/x and k was a negative constant and x>=1
Original post by big fat poo
I did so crap on my D1 i got 60 UMS I reckon so I needed 180UMS more to get an A*, thats not happening now


clearing for you mate
Reply 2683
Original post by `God
very easy paper, expect very high grade boundaries.

won't even be surprised if its 73 for A*/90UMS.

I predict:

75 -100
73 -90
70 -80
who cares about the rest


Nah fam, that's too low.
I found this paper much easier than the June 2014 one, anyone else agrees? I think the grade boundaries will be fairly standard? Also to prove cos theta on q1b I used a right angled triangle with hypothenuse sqrt(1+p^2) but when writing down the answer I copied the hypothenuse value wrong to get 1/sqrt(1-p^2). Would I get any method marks?
Original post by jennyh1
Made a couple of silly mistakes but found it fine, hopefully I got the 90 ums


highly doubt that, stop dreaming.
for temperature question, I got lambda = ln(0.5)/-40 ?
Original post by lukass
for 8b) where

sec 2y + tan 2y = 1

how did people do this?? I was so confused...


Sub in the 'show that' value from part a) for sec2y + tan 2y then it's pretty simple from there
Reply 2688
Original post by lollipopsftw
patiently waiting for Arsey


Im a noob here. Who is this arsey?
Attachment not found
Attachment not found
010.jpg
Original post by anndz3007
Here is my answer, in random order th
2p/1-p^2,1/(1-p square)^1/2, (p+1)/1-p
Ln7/2,ln3/2
51.8,-25.3
K>33/8
Coordinate=( 0,pi/3)
93 sec
3.1,13.9
-4e^-4<y<1/e something
Fx Decreasing


I got k<-2root5 and k>2root5 as it is above and below the max and min point
yh it was -4e^-4<=g(x)<=1/8e
fx is increasing
other than that seems right
You're not a member of The Student Room if you don't know Arsey. :smile:
My teacher said that it was quite easy for C3 (compared to last year and the year before) so expect high grade boundaries!
Reply 2693
Original post by Kabulkid
IT WAS EASY BUT NOT THAT EASY, i predict

75 - 100
72 - 90
68 - 80
lol if u get below an A get off TSR


75 - 100
74 - 0
Original post by Nightmare8
That's because you need 270/300 from c3 c4 and fp2 for an A*. That's for further, I don't know about the rest

He's not doing further pure math. He's doing further math which is different.
Original post by `God
very easy paper, expect very high grade boundaries.

won't even be surprised if its 73 for A*/90UMS.

I predict:

75 -100
73 -90
70 -80
who cares about the rest


Mate I totally agree with you, like that paper was p*** easy I could have done that while asleep. Actually I could have done it while doing C4 too, that's how easy it was.....STFU^^ and GTFO
Original post by Hectors
I found this paper much easier than the June 2014 one, anyone else agrees? I think the grade boundaries will be fairly standard? Also to prove cos theta on q1b I used a right angled triangle with hypothenuse sqrt(1+p^2) but when writing down the answer I copied the hypothenuse value wrong to get 1/sqrt(1-p^2). Would I get any method marks?


It said to use trig identities so I'm not sure if that would get marks. I suppose SOHCAHTOA is an identity though...
Original post by Chazley123
for temperature question, I got lambda = ln(0.5)/-40 ?


not -
Original post by Kabulkid
another one makes a rookie error, tut tut.


please go on?
If they didn't specify to give an exact value-would you still lose marks for giving decimals

Latest

Trending

Trending