The Student Room Group

c2 circles

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Original post by lolman42
subbing the equation of the line into the circle I get

7x^2 + 60x + 90 = 0

what do I do from here?:smile:


You must have realised that was wrong when you could not do part (a)
Original post by Indeterminate
Surely, as it's saying "write down", it's asking for

y=10y=\sqrt{10}


I think you have mis-read or mis-understood the question
Reply 22
Original post by TenOfThem
You must have realised that was wrong when you could not do part (a)


okay i am not too sure now

is the expansion 10x^2 + 60x + 100 = 10 ?

i did b^2-4ac but it does not equal
0

FORGET ALL WHAT i WROTE THERE!! i HAVE GOT IT NOW. what do I do for b now?
Original post by lolman42
okay i am not too sure now

is the expansion 10x^2 + 60x + 100 = 10 ?

i did b^2-4ac but it does not equal
0

FORGET ALL WHAT i WROTE THERE!! i HAVE GOT IT NOW. what do I do for b now?



So

You know know the point rom (a) so, sketch and use symmetry
Reply 24
Original post by TenOfThem
So

You know know the point rom (a) so, sketch and use symmetry


I still do not now the point

do I solve 10x^2 + 60x +90 =0 to find it?
Original post by lolman42
I still do not now the point

do I solve 10x^2 + 60x +90 =0 to find it?


yes

I suggest that you divide by 10 and use the fact that there is only one solution to spot the obvious factorisation
Reply 26
Original post by TenOfThem
yes

I suggest that you divide by 10 and use the fact that there is only one solution to spot the obvious factorisation


okay so x= -3
Original post by lolman42
okay so x= -3


Sketch and symmetry
TenOfThem's method is basically to find the intersection of the two curves, and show that there is only one intersection, so the line must be a tangent to the circle (think, if it crossed the circle there would have to be two solutions, one where it goes into the circle and one where it exits it).
Reply 29
Original post by TenOfThem
Sketch and symmetry


sorry, I am going to have to sound really silly here.

But I am lost :frown:
Original post by lolman42
sorry, I am going to have to sound really silly here.

But I am lost :frown:


Have you sketched?
Reply 31
Original post by TenOfThem
Have you sketched?


I am not exactly sure what I am meant to be sketching
Original post by lolman42
I am not exactly sure what I am meant to be sketching


A circle

x2+y2=10x^2 + y^2 = 10

and a line

y=3x+10y = 3x + 10
Reply 33
Original post by TenOfThem
A circle

x2+y2=10x^2 + y^2 = 10

and a line

y=3x+10y = 3x + 10


yep, I already had that drawn :smile:
Original post by lolman42
yep, I already had that drawn :smile:


So you have a circle

Then you have a line from (0,10) down to (-3,1)

As I say, symmetry will show you the other line
Reply 35
Original post by TenOfThem
So you have a circle

Then you have a line from (0,10) down to (-3,1)

As I say, symmetry will show you the other line


I can't see the symmetry..
Reply 36
Original post by TenOfThem
So you have a circle

Then you have a line from (0,10) down to (-3,1)

As I say, symmetry will show you the other line


surely there can only be one line passing through 0,10?
Using For Working Out Stuff P129.png

Original post by lolman42
surely there can only be one line passing through 0,10?


Well, infinite lines will pass through (0,10)

But there are 2 that pass through there and are tangents to the circle

I cannot work out why you cannot see it
(edited 11 years ago)
Reply 38
Original post by TenOfThem
Using For Working Out Stuff P129.png



Well, infinite lines will pass through (0,10)

ohhh i was doing something different, so the coordinates at the new point of contact are 3,1? :tongue:

But there are 2 that pass through there and are tangents to the circle

I cannot work out why you cannot see it

ohhh i was doing something different, so the coordinates at the new point of contact are 3,1? :tongue:
Original post by lolman42
ohhh i was doing something different,


I am intrigued

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