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    What did everyone get for the 3 mark calculation questions?
    I got 2.4 for the first one and 12.5 for the second one
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    (Original post by chrlhyms)
    I would love them to ask me to draw an ester or carboxylic acid, easy marks which a lot of people couldn't get, and yeah i hope a good 4 mark on titrations comes up and other maths
    You are soooo unbelievably lucky. Just, just that/
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    (Original post by TSlayerr)
    Moles over vols (concentration). My teacher says this phase all the time. That's why I remember the formula
    This helped me in the exam! Thanks haha!


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    (Original post by alan_jjj)
    What did everyone get for the 3 mark calculation questions?
    I got 2.4 for the first one and 12.5 for the second one
    I got the same!
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    (Original post by SophFlorence)
    I got the same!
    Hey, what did you get for the impure copper one, 4 marker on electrolysis? And the two 6 markers?
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    (Original post by XherdanXhaka)
    Hey, what did you get for the impure copper one, 4 marker on electrolysis? And the two 6 markers?
    For the 4 marks I just said something like: The cathode is the pure copper and anode is the impure. I said how the direct current pulls electrons off of the anode, and that the copper atoms change to copper (Cu+) ions. They are attracted to the cathode... Blah blah blah.

    Then for 6 marks:

    First 6 marker:
    -You get precise amount of acid needed to neutralise
    -Means that universal indicator not needed, which would contaminate the solution
    -Left with salt-water
    -Heat solution gently
    -Left with salt alone
    -Flush salt with distilled water
    -Leave to dry on filter paper

    Second six mark:
    -Substance A=Alkene/ unsaturated hydrocarbon
    -Turns bromine water colourless
    -Due to 'spare bonds' in the Alkene
    -Substance B=Alcohol as it consists of 'COH'- to be precise- C(n)H(2n+1)OH
    -Substance C=Carboxylic acid
    -Substance D= Alkane

    I could be wrong, but that's what I thought


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    (Original post by SophFlorence)
    For the 4 marks I just said something like: The cathode is the pure copper and anode is the impure. I said how the direct current pulls electrons off of the anode, and that the copper atoms change to copper (Cu+) ions. They are attracted to the cathode... Blah blah blah.

    Then for 6 marks:

    First 6 marker:
    -You get precise amount of acid needed to neutralise
    -Means that universal indicator not needed, which would contaminate the solution
    -Left with salt-water
    -Heat solution gently
    -Left with salt alone
    -Flush salt with distilled water
    -Leave to dry on filter paper

    Second six mark:
    -Substance A=Alkene/ unsaturated hydrocarbon
    -Turns bromine water colourless
    -Due to 'spare bonds' in the Alkene
    -Substance B=Alcohol as it consists of 'COH'- to be precise- C(n)H(2n+1)OH
    -Substance C=Carboxylic acid
    -Substance D= Alkane

    I could be wrong, but that's what I thought


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    C is Ethanoic* acid but yeah, but the first 6 marker, it said it had to be done by titration? I just talked about titration then the Preparing Soluble Salts (1) in the book. I did (2) and (1).
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    (Original post by XherdanXhaka)
    C is Ethanoic* acid but yeah, but the first 6 marker, it said it had to be done by titration? I just talked about titration then the Preparing Soluble Salts (1) in the book. I did (2) and (1).
    Yes. I did write about the titration, but I didn't go in to too much depth on it. I more so talked about the actual preparing of the salt.


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    (Original post by SophFlorence)
    Yes. I did write about the titration, but I didn't go in to too much depth on it. I more so talked about the actual preparing of the salt.


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    I just talked about both lol and hoped to get the marks. And the temperature linked with Haber Process, why not a higher temp used?
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    (Original post by XherdanXhaka)
    I just talked about both lol and hoped to get the marks. And the temperature linked with Haber Process, why not a higher temp used?
    It's because it would favour the endothermic reaction, meaning the percentage yield of ammonia would lessen.


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    (Original post by SophFlorence)
    It's because it would favour the endothermic reaction, meaning the percentage yield of ammonia would lessen.


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    Think I talked about that too. So overall 48-51 A*?
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    (Original post by XherdanXhaka)
    Think I talked about that too. So overall 48-51 A*?
    That's good. Yeah, probably.


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    (Original post by SophFlorence)
    That's good. Yeah, probably.


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    Lol that 1 marker that needed you to do the calculations? Like wth? I got 12.5 and 0.4 i think for one of them.
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    (Original post by XherdanXhaka)
    Lol that 1 marker that needed you to do the calculations? Like wth? I got 12.5 and 0.4 i think for one of them.
    So did I. I got 0.1 for the 1 marker.


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    I don't recall getting 0.4- I got 2.4 for one of them.


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    (Original post by SophFlorence)
    I don't recall getting 0.4- I got 2.4 for one of them.


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    yeah 2.4 lol, 0.1 x 24. You got an unofficial mark scheme?
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    (Original post by XherdanXhaka)
    yeah 2.4 lol, 0.1 x 24. You got an unofficial mark scheme?
    I haven't sorry


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    (Original post by SophFlorence)
    I haven't sorry


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    Nvm, you look good btw
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    What did you write for the question about the dissolved solids in hard water- it was a question like how would you identify them without using soap. I put adding Sodium Hydroxide and then white precipitate for identifying calcium ions. Is that right?


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