c3 range question please help!!!

was this from june 09?

yeee

Are you told what the equation for f(x) is, and are you given any other information in parts a and b?

ahhh, i sat that paper! can't actually remember the answer to this question though, sorry

here is the rest of the question

For exponential functions the range is f(x)>0 since they approach but never touch the line y=0 ( the asymptote).

However, in this question you should apply transformation. It's shifted vertically by 'K' units in the negative direction.

Therefore, the new range will be f(x)>-k

the range is y > -k , as it's just the y = ex graph shifted down by k (it's now asymptotic to y = -k instead of y = 0).

range is always y, the domain is always x.

edit: well in this case, you could put it as f(x) > -k (which is still basically the same as y > -k)

thanks that made it clear

For exponential functions the range is f(x)>0 since they approach but never touch the line y=0 ( the asymptote).

However, in this question you should apply transformation. It's shifted vertically by 'K' units in the negative direction.

Therefore, the new range will be f(x)>-k

but what about the y values below -k as -8 will have an y value less than -k is taht so??

The range of a function is the set of values which y can take.

In this question we've found out that the range is f(x)>-k i.e. the function cannot take y values below -k.

-k is the new horizontal asymptote instead of the line y=0 (the x-axis)