Hi. I know that when CH3CH2OH + CH3COOH react , this produces (with a H+ catalyst) CH3COOCH2CH3 + H2O.
However, what happens when the hydroxy (OH) group is on the 2nd carbon, so, for example. Help me with these two (ie complete the equations and explain please!)
1) PROPAN-2-OL + ETHANOIC ACID
CH3CH(OH)CH3 + CH3COOH ->(this is supposed to be an equilibrium sign)
2) BUTAN-2-OL + ETHANOIC ACID
CH3CH2CH(OH)CH3 + CH3COOH ->(again, this is supposed to be an equilibrium sign)
Please complete the above 2 equations, and explain your answers, name the products as well if you have time (although I could do that easily, so maybe not)