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    Discuss all your enquiries and queries leading up to the exam How are people preparing? Good luck
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    Been doing a few past papers and there seems to be a lot of questions on chapter 7 (hypothesis testing) which can be a little confusing.
    Does anyone have past papers from 2010?
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    (Original post by cpdavis)
    Discuss all your enquiries and queries leading up to the exam How are people preparing? Good luck
    Subscribed

    (I was expecting this from you when I saw C3...but I thought there was already one)
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    (Original post by atofu)
    Been doing a few past papers and there seems to be a lot of questions on chapter 7 (hypothesis testing) which can be a little confusing.
    Does anyone have past papers from 2010?
    Not started yet, but will start papers soon..
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    (Original post by cpdavis)
    Discuss all your enquiries and queries leading up to the exam How are people preparing? Good luck
    By doing past papers
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    I have little problem in this question 3.
    I have got part a-c correct but don't understand the answer to part d which edexcel provided on markscheme.
    In part d, they specified that the robot break down twice but in part b the robot break down at least once(it can be more than twice), so why the answer to part d is equal to part b???

    Thankss
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    (Original post by jit987)
    Not started yet, but will start papers soon..
    thanks for the papers
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    (Original post by cazzy-joe)
    I have little problem in this question 3.
    I have got part a-c correct but don't understand the answer to part d which edexcel provided on markscheme.
    In part d, they specified that the robot break down twice but in part b the robot break down at least once(it can be more than twice), so why the answer to part d is equal to part b???

    Thankss
    Part D is asking for the probability of the robot breaking down in the next 8 hours (you ignore the bit where it says it broke down twice in the last 8 hours as it's not asking about that in the probability - poisson events are independent)
    And in part B i , breaking down atleast once = breaking down so the answer is just the same.


    I have a question, I don't understand the last part of this question in the june 2008 paper. It says find the probability of incorrectly rejecting the Ho, but in the answer they just worked out the probability of rejecting the Ho?
    I don't see how they would be rejecting it incorrectly then. What i thought was working out the actual significance and do 5% - that to find the probability of it being rejected, if 5% was the one they used instead of the actual significance.. if that makes sense :confused:

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    (Original post by atofu)
    I have a question, I don't understand the last part of this question in the june 2008 paper. It says find the probability of incorrectly rejecting the Ho, but in the answer they just worked out the probability of rejecting the Ho?
    I don't see how they would be rejecting it incorrectly then. What i thought was working out the actual significance and do 5% - that to find the probability of it being rejected, if 5% was the one they used instead of the actual significance.. if that makes sense :confused:

    Yeh, that is weird. The mark scheme would be right if they question said 'Probability of rejecting Ho'.

    Can anyone explain why the MS for Jan 2007 Question 3b) says is P(W>or equal 7). Where and how do I get that?
    Thanks.
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    (Original post by jit987)
    Yeh, that is weird. The mark scheme would be right if they question said 'Probability of rejecting Ho'.

    Can anyone explain why the MS for Jan 2007 Question 3b) says is P(W>or equal 7). Where and how do I get that?
    Thanks.

    Each box has 12 flowers, to get more white flowers you would need atleast 7 of the flowers to be white which is p(w> or equal to 7)
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    (Original post by atofu)
    Part D is asking for the probability of the robot breaking down in the next 8 hours (you ignore the bit where it says it broke down twice in the last 8 hours as it's not asking about that in the probability - poisson events are independent)
    And in part B i , breaking down atleast once = breaking down so the answer is just the same.
    But then even part c is also breaking down (two times) then why cant answer d be that??


    I have a question, I don't understand the last part of this question in the june 2008 paper. It says find the probability of incorrectly rejecting the Ho, but in the answer they just worked out the probability of rejecting the Ho?
    I don't see how they would be rejecting it incorrectly then. What i thought was working out the actual significance and do 5% - that to find the probability of it being rejected, if 5% was the one they used instead of the actual significance.. if that makes sense :confused:
    Yeahh I think they found out probability for REJECTING Ho.
    So then probability of INCORRECTLY REJECTING would be 1-0.0433=0.9567???
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    (Original post by atofu)
    Each box has 12 flowers, to get more white flowers you would need atleast 7 of the flowers to be white which is p(w> or equal to 7)
    Alright
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    (Original post by cazzy-joe)
    But then even part c is also breaking down (two times) then why cant answer d be that??
    For part D they are asking the prob. that the robot will break down at all, so that could mean breaking down once, twice, 3 times etc. etc.
    which is the same as the probability of breaking down atleast once (part b)
    Part c is just specific to the robot breaking down twice, but if it did break down at all, it could be more or less than breaking down 2 times.. if you get what i mean xD
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    (Original post by atofu)
    For part D they are asking the prob. that the robot will break down at all, so that could mean breaking down once, twice, 3 times etc. etc.
    which is the same as the probability of breaking down atleast once (part b)
    Part c is just specific to the robot breaking down twice, but if it did break down at all, it could be more or less than breaking down 2 times.. if you get what i mean xD
    Okay.. i get it now..
    Thanks
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    (Original post by jit987)
    Not started yet, but will start papers soon..
    Thanks for the papers jit987
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    Hi guys. I've got a question which I'm slightly confused by. Here it goes. 'The random variable X follows a continuous uniform distribution in the interval [2,11].'. 'Find P(|X-5|<2)'. Thanks in advance.
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    Anyone going to attempt any Solomon Papers before the exam?
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    Is it allowed to use black ink in the exams????

    I cant see it mention anywhere so just want to confirm
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    (Original post by cazzy-joe)
    Is it allowed to use black ink in the exams????

    I cant see it mention anywhere so just want to confirm

    Yeah you have to, because they scan the papers in :yep:
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    (Original post by cpdavis)
    Yeah you have to, because they scan the papers in :yep:
    Why do they have to scan in???? I never knew this before and I never use black ink in exams
 
 
 
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