GPODT
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I done 1a) and got a = 0.7 m/s2, however I am unsure on how to do 1b). I mean P = Fv, and F hasn't changed nor has v so why does P change? Maybe I am understanding F wrong, is F the resultant force or just the traction?

Also, I got the right velocity for 2a) but what angle are they referring to in 2b? I mean there is two possible angles:

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GPODT
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cooldudeman
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(Original post by GPODT)

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for 1b) P=Fv, you've got the v so you need to find the F which is the driving/forward force. its moving at constant speed so the acceleration=0, so if you resolve up the inclined plane, you have, F - 750 - 1500gsin(a) = 1500(0)
which gives you the force.

for 2b) it always asks for the inside angle, which is theta on your diagram.
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GPODT
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(Original post by cooldudeman)
for 1b) P=Fv, you've got the v so you need to find the F which is the driving/forward force. its moving at constant speed so the acceleration=0, so if you resolve up the inclined plane, you have, F - 750 - 1500gsin(a) = 1500(0)
which gives you the force.

for 2b) it always asks for the inside angle, which is theta on your diagram.
Ah I see! Thanks
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