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AQA CHEM5 A2 Chemistry - 19th June 2013

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Reply 2480
I can't stop crying
Original post by Pinkhead
i thought it asked you to suggest an experiment to prove that the bonding is ionic?


There were a couple about MgO. One was that question, then another asked you to show a reaction demonstrating it as a base
Original post by cat-lover
I highly doubt that. XD I've probably dropped a lot more anyway but just can't remember. I do need an A* though because I got a C in chemistry unit 4 because I got food poisoning. :frown:


Look at the past boundaries on the AQA website it's usually about 81 for an A*
Reply 2483
I'm sorry the examiner was obviously going through a divorce so he intended to take his revenge on me
Kill me
Original post by SpiggyTopes
You did, you melt it and if it conducts then it's ionic. :-)


damn... I just said try to dissolve it in water, LOL. I was pushed for time so i wrote the first time that came to mind: solubility.
Reply 2485
Anyone know what the overall UMS is for each grade boundary please?
Original post by extons
CH3CHO + Co3+ + H2O > Co2+ + CH3COOH + 2H+ + e-
2H+ + CH3CHO + O2 + Co2+ + e- > Co3+ + CH3COOH + H2O

Two catalytic equations.


I used [Co(H2O)6]2+ in place of Co2+, will I still get the marks?
Reply 2487
I didn't have any electrons in the question involving cobalt as a catalyst



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Reply 2488
Ive lost about 25 marks so a B/C ****tttttt
Bye bye university
Original post by SpiggyTopes
Look at the past boundaries on the AQA website it's usually about 81 for an A*


Well hopefully it's lower this year and I haven't made anymore stupid mistakes. :smile:
Original post by dizzy17
what was the equation and colours for the aluminium in excess ammonia?


Well I put:

[Al(H2O)6]3+ + 6NH3 --> [Al(OH)6]3- + 6NH4+

From colourless soln to colourless soln (although white ppt is formed, it redissolves).
Reply 2491
Original post by Az_016
I didn't have any electrons in the question involving cobalt as a catalyst



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thats correct - you weren't supposed to have any :smile: The guy that posted before is obviously dead clever cos he got the correct ratio.. but I am rather confident that his coblat answers are wrong :P sorry :smile:
Original post by Anshul91
Anyone know what the overall UMS is for each grade boundary please?


How can anyone possibly know that when they haven't been released yet?

Why neg for telling the truth? Klkl
(edited 10 years ago)
Original post by loknath
If lost about 25 marks so a B/C ****tttttt
Bye bye university


that would be an A even with high boundaries mate
Original post by loknath
Ive lost about 25 marks so a B/C ****tttttt
Bye bye university


75 is usually an A, ****ing hell.
What was the answer to why was CO2 released or something like that the one marker?
Reply 2496
Original post by loknath
Ive lost about 25 marks so a B/C ****tttttt
Bye bye university


75/100 was a high A last year
Original post by Pinkhead
damn... I just said try to dissolve it in water, LOL. I was pushed for time so i wrote the first time that came to mind: solubility.


That might be right too. It depends if the molecule is soluble or not. I can't remember what the molecule was so don't know if it's soluble. :-) Fingers crossed it's soluble!
Original post by mulac1
yes I suppose you could have done that ... but it doesnt really react with water...
I reacted it with HCl to give MgCl2 and water




Maybe it was a mark for h2o as steam
Original post by loknath
I can't stop crying



Cheer up:smile: It can't be that bad. Don't worry, It was a tough paper and I too struggled despite all the revision I put in.

Lets hope the grade boundaries are lower if everyone found it very hard. :smile:

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