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I am, after M1 I have a feeling this one will be hard too 
I think the paper is much easier than the january one
It was easier than I thought it would be!
Posted from TSR Mobile
Posted from TSR Mobile
Any one get these:
1) (I) (2,2)
ii) y+3x=8
2) y=f(x-1)
y=-f(x)
3) -1-root3
4) a) 3x2 +1/2rootx -0.25 -1/2x2
b) (-2,-9)
5) (I) x+3)2 +8
ii)(-3,8) min
iii)x>-3 x<-3
iv)y>8
b) x= -5/6
6) a=9
b=-12
c= 4
ii) x=2/3
7ii) 3x4x6
8) k>-5+2root5 and k<-5-2root5
1) (I) (2,2)
ii) y+3x=8
2) y=f(x-1)
y=-f(x)
3) -1-root3
4) a) 3x2 +1/2rootx -0.25 -1/2x2
b) (-2,-9)
5) (I) x+3)2 +8
ii)(-3,8) min
iii)x>-3 x<-3
iv)y>8
b) x= -5/6
6) a=9
b=-12
c= 4
ii) x=2/3
7ii) 3x4x6
8) k>-5+2root5 and k<-5-2root5
Original post by student1696
Any one get these:
1) (I) (2,2)
ii) y+3x=8
2) y=f(x-1)
y=-f(x)
3) -1-root3
4) a) 3x2 +1/2rootx -0.25 -1/2x2
b) (-2,-9)
5) (I) x+3)2 +8
ii)(-3,8) min
iii)x>-3 x<-3
iv)y>8
b) x= -5/6
6) a=9
b=-12
c= 4
ii) x=2/3
7ii) 3x4x6
8) k>-5+2root5 and k<-5-2root5
1) (I) (2,2)
ii) y+3x=8
2) y=f(x-1)
y=-f(x)
3) -1-root3
4) a) 3x2 +1/2rootx -0.25 -1/2x2
b) (-2,-9)
5) (I) x+3)2 +8
ii)(-3,8) min
iii)x>-3 x<-3
iv)y>8
b) x= -5/6
6) a=9
b=-12
c= 4
ii) x=2/3
7ii) 3x4x6
8) k>-5+2root5 and k<-5-2root5
I got nearly all the same as you apart from BIB:
5.(iv) y greater than or equal to 8
5.(b) x = -1/2
You might be right regarding 5 (iv), I can't see where I've gone wrong on 5(b)? You've got me worried now.
I often hate these post mortoms comparing answers to others, finding I've fvcked something up.
I was getting 70+ in a lot of the past papers so if I get anything less than that I'll be pretty pissed off.
(edited 10 years ago)
Oh I know what I've done wrong.
I cross multiplied (3^(x+1) x 3^2x)(3^3/2) = 1
And then left hand side equaled 3x+5/2 = 1
And basically I forgot to change the 1. Idiot.
How many marks will I lose? All them? I'm hoping for some method marks.
I cross multiplied (3^(x+1) x 3^2x)(3^3/2) = 1
And then left hand side equaled 3x+5/2 = 1
And basically I forgot to change the 1. Idiot.
How many marks will I lose? All them? I'm hoping for some method marks.
Original post by Sharpshooter
Oh I know what I've done wrong.
I cross multiplied (3^(x+1) x 3^2x)(3^3/2) = 1
And then left hand side equaled 3x+5/2 = 1
And basically I forgot to change the 1. Idiot.
How many marks will I lose? All them? I'm hoping for some method marks.
I cross multiplied (3^(x+1) x 3^2x)(3^3/2) = 1
And then left hand side equaled 3x+5/2 = 1
And basically I forgot to change the 1. Idiot.
How many marks will I lose? All them? I'm hoping for some method marks.
X= -5/6
you were correct!
Original post by student1696
Any one get these:
1) (I) (2,2)
ii) y+3x=8
2) y=f(x-1)
y=-f(x)
3) -1-root3
4) a) 3x2 +1/2rootx -0.25 -1/2x2
b) (-2,-9)
5) (I) x+3)2 +8
ii)(-3,8) min
iii)x>-3 x<-3
iv)y>8
b) x= -5/6
6) a=9
b=-12
c= 4
ii) x=2/3
7ii) 3x4x6
8) k>-5+2root5 and k<-5-2root5
1) (I) (2,2)
ii) y+3x=8
2) y=f(x-1)
y=-f(x)
3) -1-root3
4) a) 3x2 +1/2rootx -0.25 -1/2x2
b) (-2,-9)
5) (I) x+3)2 +8
ii)(-3,8) min
iii)x>-3 x<-3
iv)y>8
b) x= -5/6
6) a=9
b=-12
c= 4
ii) x=2/3
7ii) 3x4x6
8) k>-5+2root5 and k<-5-2root5
they are all identical to my answers!!
Thanks guys seems like I done well then 
5b I got -1/9
Posted from TSR Mobile
Posted from TSR Mobile
Original post by K995
I got thought it was wrong so was frantacilly trying to do that question again in the hope of getting an integer or something. Thankfully I ran out of time and did not change it.
Original post by student1696
Thanks guys seems like I done well then
you've definately secured 90UMS+
I have just realised I will drop a mark in the transformation question
Original post by condor789
X= -5/6
you were correct!
you were correct!
What do you mean I was correct?
Does anyone know how many marks I would lose? Would I get any method marks for that?
My overall total is going to be 63+ any method marks for 5(b).
(edited 10 years ago)
Original post by Sharpshooter
What do you mean I was correct?
Does anyone know how many marks I would lose? Would I get any method marks for that?
Does anyone know how many marks I would lose? Would I get any method marks for that?
if you have used rules of indicies you'll get marks for each rule you used correct
Original post by K995
I got -1/9 too
Would somebody kindly put up working solutions for 5(b)? I just want to see where I went wrong and deduce how many marks I would likely to get. Thanks.
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