If you remove the bromine atom (and, of course, one hydrogen), there are three possible positions in which a C=C bond could form:
-Between the central carbon in the CH(CH3)2 group and the carbon in the C-Br.
-Between the carbon in the CH3 and the carbon in the C-Br.
-Between the carbon in the CH2 and the C-Br.
Try drawing the structures of each of these three possible alkenes. Any where there are 2 different groups on each carbon in the C=C bond will form a pair of E/Z isomers.
Edit: oops responded to the wrong post, meant to quote the original. Wow I’m tired lol.
Just a heads up, this type of question does assess content that comes up in the specifications for all the major UK exam boards- including OCR A and B. You may be asked something similar in your actual exams.
If you remove the bromine atom (and, of course, one hydrogen), there are three possible positions in which a C=C bond could form:
-Between the central carbon in the CH(CH3)2 group and the carbon in the C-Br.
-Between the carbon in the CH3 and the carbon in the C-Br.
-Between the carbon in the CH2 and the C-Br.
Try drawing the structures of each of these three possible alkenes. Any where there are 2 different groups on each carbon in the C=C bond will form a pair of E/Z isomers.
Edit: oops responded to the wrong post, meant to quote the original. Wow I’m tired lol.
Is this what the molecules are supposed to look like? Also, how am I supposed to get the correct answer in under a minute?
Is this what the molecules are supposed to look like? Also, how am I supposed to get the correct answer in under a minute?
If the bromoalkane you copied down was correct, you would have drawn the correct alkenes- but you missed one carbon on the molecule and that does affect the answer.
Yeah, you need longer than a minute to answer that question imo.